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2 years ago

Which object would have MORE kinetic energy?

Physics

2 answers:

GuDViN [60]2 years ago

7 0

Answer:

$energy \: = \frac{1}{2} m {c}^{2} \\ energy \: is \: directly \\ \: protional \: to \: mass \\ the \: hevier \: the \: object \\ the \: more \: k.e.$

valentinak56 [21]2 years ago

6 0

Answer:

A dump truck going 70 mph

Explanation:

hope it helps you

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What is a likely consequence of continued human population growth

quester [9]

Answer:

Rapid human population growth has a number of consequences. Population grows fastest in the world's poorest countries. High fertility rates have historically had a strong relation with poverty, and high childhood mortality rates

Explanation:

i got it from goo.gle but i hope that helps:)

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3 years ago

What do you think will happen to dirt and rocks on the Mountainside when the ice melts

AlekseyPX

This question is personal preference... just answer with whatever YOU think, there probably isn’t s wrong answer if I’d guess.

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3 years ago

A body is electrically neutral. Does it mean that it has no charge?<br>

vova2212 [387]

Answer:

If a body is electrically neutral it means it has no net charge.

Explanation:

Because it has the same number if protons as it does electron , which are opposite charges that offset eachother.

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3 years ago

Ball A 1.55kg moving right at 8.76 m/s makes a head-on collision with ball B (0.752 kg) moving left at 11.4 m/s. After, ball B m

Illusion [34]

1.15 m/s to the left (3 sig. fig.).

<h3>Explanation</h3>

Momentum is conserved between the two balls if they are not in contact with any other object. In other words,

$p_{\text{A,initial}} + p_{\text{B,initial}}=p_{\text{A,final}} + p_{\text{B,final}}$

$m_\text{A} \cdot v_{\text{A,initial}} + m_\text{B}\cdot v_{\text{B,initial}}=m_\text{A}\cdot v_{\text{A,final}} + m_\text{B}\cdot v_{\text{B,final}}$ , where

$m$ stands for mass and
$v$ stands for velocity, which can take negative values.

Let the velocity of objects moving to the right be positive.

$m_\text{A} = 1.55\;\text{kg}$ ,
$m_\text{B} = 0.752\;\text{kg}$ .

Before the two balls collide:

$v_\text{A} = +8.76\;\text{m}\cdot\text{s}^{-1}$ ,
$v_\text{B} = -11.4\;\text{m}\cdot\text{s}^{-1}$ .

After the two balls collide:

$v_\text{A}$ needs to be found,
$v_\text{B} = +9.03\;\text{m}\cdot\text{s}^{-1}$ .

Again,

$m_\text{A} \cdot v_{\text{A,initial}} + m_\text{B}\cdot v_{\text{B,initial}}=m_\text{A}\cdot v_{\text{A,final}} + m_\text{B}\cdot v_{\text{B,final}}$ ,

$1.55 \times (+8.76) + 0.752 \times (-11.4) = 1.55\;{\bf v_{\textbf{A,final}}} + 0.752 \times (+9.03)$ .

$v_{\text{A,final}} = \dfrac{1.55 \times (+8.76) + 0.752 \times (-11.4)-0.752 \times (+9.03)}{1.55} = -1.15\;\text{m}\cdot\text{s}^{-1}$ .

$v_{\text{A,final}}$ is negative? Don't panic. Recall that velocities to the right is considered positive. Accordingly, negative velocities are directed to the left.

Hence, ball A will be travelling to the left at 1.15 m/s (3 sig. fig. as in the question) after the collision.

8 0

3 years ago

Read 2 more answers

If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is φ, what wo

Svetradugi [14.3K]

the correct answer is if you tripled the sphere volume, do the mat idiot

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2 years ago