Sodium Phosphide has a formula of Na3P . In order to bond ionically the charges must be equal and opposite. It will take one -3 phosphide ion to balance three +1 sodium ions forming a magnesium phosphide molecule of Na3P
52
Explanation:
We need to understand and apply the rules of significant figures when carrying out addition operations to solve this problem:
Rules of significant figures:
- Non-zero digits are always significant in a given number
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion is significant.
- Any leading zero in a decimal is significant.
In addition, the answer of the sum is given to the least number of significant digits of the given numbers:
44.2124
+ 0.81
+ 7.335
sum 52.3574
Now the least number of significant figure is 2 as seen in 0.81
we round the sum up to 52
learn more:
Significant numbers brainly.com/question/6384538
#learnwithBrainly
The reaction CFCl3 + UV Light -> CFCl2 + Cl does not need another reactant as with CFCl3 because the reaction itself is reactive to light. Note that there are reactions that are sensitive to light to form products and when this type of reaction are not exposed to light, no reaction occurs.
Answer:The equilibrium constant for a given reaction is [concentration of products]/[concentration of reactants].
Explanation:
Equilibrium constant=[concentration of products]/[concentration of reactants]
The concentration of reactant molecules is maximum at time 0 and it decreases as the reaction proceeds, The concentration of product molecules increases.At equilibrium the concentration of reactants and products are equal.
All the changes would occur in accordance with the LeChateliers principle.
For the given reaction the following changes would occur:
a When CO is removed from the reaction mixture so the reaction would shift towards right that is in forward direction as we are decreasing the concentration of CO so the system would try to increase the concentration of CO and that can happen by more production of CO.
b Since the above reaction is an endothermic reaction so when we would be adding heat to the system that is when we would increase the temperature the reaction would shift forwards as more heat energy is absorbed by reactants to form more products.
c When more CO₂ is added so more amount of reactants are added to the system so the system would try to decrease the amount of reactants that is CO₂ and hence more amount of products would be formed.The reaction would shift in forward direction.
d Since this reaction is endothermic in nature so when we remove the heat from reaction hence even less amount of heat is present in the system and so the reaction shift in backward direction as the reaction cannot proceed without enough amount of heat.
