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Damm [24]
2 years ago
12

How would one convert 15 seconds to hours?

Chemistry
2 answers:
laiz [17]2 years ago
8 0

Explanation:

a ...15 seconds×(3600 seconds hour)

frozen [14]2 years ago
3 0

15 seconds x 1 hour/3600 seconds

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Nitrogen and hydrogen react to produce ammonia. What mass of ammonia could be produced from 500 grams of nitrogen? Assume that e
OlgaM077 [116]
The answer is 607g. the working is shown above.

5 0
3 years ago
For the reaction co(g)+2h2(g)<->ch3oh(g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch
SVETLANKA909090 [29]
The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃<span>OH(g)

Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
   k = [</span>CH₃OH(g)] / [CO(g)] [H₂(g) ]²

By substitution,
   k = 0.030 M / 0.020 M x (<span>0.072 M</span>)²
   k = 289.35 M⁻²
6 0
3 years ago
Which of the following transitions represent the emission of a photon with the largest energy?
s2008m [1.1K]

Answer:

n=6 to n=3 (B)

Explanation:

Energy of an electron present in the n^{th} orbit is directly proportional to n^{2} .Hence a transistion from one orbit to another orbit emits an energy proportional to the difference of their squares of the orbits. that is if an electron travels from orbit n1 to orbit n2 then it emits an energy corresponding to n_{1} ^{2} -n_{2} ^{2}.So in the above question the highest energy emission occurs when an electron moves from n=6 to n=3.(Highest difference of energy levels).

6 0
3 years ago
1) A toy car with a mass of 2.35 kg is pushed with a force of 21.6 N. What is the acceleration of the car?
Nataly_w [17]

Answer:

The acceleration of the car is 9,19 m/s2

Explanation:

We use the formula: F=m x a---> a=F/m

a=21,6N/ 2,35kg       1N is 1kgxm/s2

a=21,6 kg x m/s2 x 2,35 kg

a=9,191489362  m/s2

6 0
3 years ago
For the reaction of hydrogen with iodine
fenix001 [56]

Answer:

r_{H_2} = \frac{-1}{2} r_{HI}

Explanation:

Hello!

In this case, considering the given chemical reaction:

H_2(g) + I_2(g) \rightarrow 2HI(g)

Thus, by applying the law of rate proportions, we can write:

\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

r_{H_2} = \frac{-1}{2} r_{HI}

Best regards!

8 0
2 years ago
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