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Anna35 [415]
4 years ago
5

As someone falls toward the Earth, what happens to their GPE?

Chemistry
1 answer:
Dimas [21]4 years ago
3 0
<h3>Answer:</h3>

B. Decreases

<h3>Explanation:</h3>
  • The potential energy or stored energy possessed by an object relative to the earth's gravity is known as gravitational potential energy, GPE.
  • This energy depends on the position of the object from the earth's surface and its weight.
  • It is given by, GPE = mass × height × gravitational acceleration
  • Therefore, a heavier object has more gravitational potential compared to a lighter object at the same height.
  • Additionally, an object at a higher height from the surface of the earth will possess more gravitational potential energy compared to an object near the earth's surface.

In this case;

  • We would, therefore, conclude that when someone falls towards the earth his/her gravitational potential energy (GPE) decreases due to a decrease in height from the surface of the earth.
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Which has the higher percentage of aluminum, Al2O, or Al(NO3)3
Rzqust [24]

Al₂O  has a higher percentage of aluminium.

Explanation:

To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:

Molar mass of Al₂O = 2(27) + 16 = 70g/mol

Molar mass of Al(NO₃)₃ = 27 + 3[14 + 3(16)] = 213g/mol

Percentage by mass of Al in Al₂O = \frac{2x27}{70} x 100 = 77%

Percentage by mass of Al in  Al(NO₃)₃ = \frac{27}{213} x 100 = 12.7%

Al₂O  has a higher percentage of aluminium.

learn more:

Molar mass brainly.com/question/2861244

#learnwithBrainly

8 0
3 years ago
Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

\qquad \sf  \dashrightarrow \:  \approx4.7 \times 10 {}^{23}  \:  \:  \: molecules

5 0
2 years ago
CORRECT ANSWER GETS BRAINLIST
pashok25 [27]

Answer:

B. halocline

Explanation:

it is a zone in the oceanic water that changes depending on the depth

Hope This Helped Sorry If Wrong

6 0
2 years ago
A sample of methane gas, CH4, occupies 3.25 L at temperature of 19.0 o C. If the pressure is held constant, what will be the tem
Artemon [7]

Answer:

625.46 °C

Explanation:

We'll begin by converting 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 19 °C

T(K) = 19 °C + 273

T(K) = 292 K

Next, we shall determine the Final temperature. This can be obtained as follow:

Initial volume (V₁) = 3.25 L

Initial temperature (T₁) = 292 K

Final volume (V₂) = 10 L

Final temperature (T₂) =?

V₁/T₁ = V₂/T₂

3.25 / 292 = 10 / T₂

Cross multiply

3.25 × T₂ = 292 × 10

3.25 × T₂ = 2920

Divide both side by 3.25

T₂ = 2920 / 3.25

T₂ = 898.46 K

Finally, we shall convert 898.46 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 898.46 K

T(°C) = 898.46 – 273

T(°C) = 625.46 °C

Therefore the final temperature of the gas is 625.46 °C

4 0
3 years ago
PLZ HELP
nika2105 [10]
Mjdksksksnsjdkjdjsksksjdndnd
8 0
4 years ago
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