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harkovskaia [24]
3 years ago
9

PLEASE HELP DUE TOMORROW

Chemistry
1 answer:
allsm [11]3 years ago
7 0

Answer:

2CO₂ ⇄ 2CO + O₂.

Explanation:

  • <em>The equilibrium constant (Keq)</em> for a reaction is the ratio of the concentration of the products to the reactants, each one is raised to each molar coefficient.

So, for Keq = [CO]²[O₂]/[CO₂]²,

It is clear that the products are CO and O₂, while the reactant is CO₂.

So, the reaction for this is:

<em>2CO₂ ⇄ 2CO + O₂.</em>

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In the following reaction, 451.4 g of lead reacts with excess oxygen forming 365.0 g of lead(II) oxide. Calculate the percent yi
user100 [1]
Let MM(x) be the molar mass of x.

MM(Pb) : MM(PbO)
=207.21 : 223.20  =  451.4 g : x g

cross multiply and solve for x
x=223.2/207.21*451.4
= 486.23 g

Percentage yield = 365.0/486.23= 0.75067 = 75.07% (rounded to 4 sign. fig.)

4 0
3 years ago
How do you calculate the mass of a product when the amounts of more than one reactant are given?
chubhunter [2.5K]

you add the masses of the reactants, because of conservation of mass. if there are two or more products they will ask you to find the mass of only one product or the sum of the mass of all products

3 0
3 years ago
In the name carbon dioxide what does the prefix of the second word indicate about a molecule of a dioxide A. It has two carbon a
brilliants [131]

Answer:

The answer is option B, that is, it has two oxygen atoms.

5 0
2 years ago
En un matraz, disponemos de 100 g de gas oxígeno que se encuentran a 1 at de presión y 273 K de temperatura. Calcular : a) el nú
Misha Larkins [42]

Answer:

Explanation:

Dado que:

masa de oxígeno gaseoso = 100 g

presión = 1 atm

temperatura = 273 K

(a)

número de moles de oxígeno contenidos en el matraz = masa de oxígeno / masa molar de oxígeno

= 100 g / 16 gmol⁻¹

= 6.25 moles

(b) El número de moléculas de oxígeno es el siguiente:

Dado que 1 mol de oxígeno gaseoso contiene 6.023 * 10²³ moléculas de oxígeno.

Entonces, 6.25 moles contendrán:

= (6.25 ×  6.023 * 10²³) moléculas de oxígeno.

≅ 3.764 × 10²³ moléculas de oxígeno.

(c) El número de átomos de oxígeno es:

= 2 × 3.764 × 10²³

= 7.528 × 10²³ átomos de oxígeno

(d) Usando la ecuación de gas ideal

PV = nRT

El volumen ocupado por el oxígeno = \dfrac{nRT}{P}

Volumen ocupado por oxígeno = \dfrac{ 6.25 * 8.314 *273}{1}

Volumen ocupado por oxígeno= 14185.76 m³

3 0
3 years ago
In an internal combustion engine, platinum speeds up the oxidation of carbon monoxide to carbon dioxide. Platinum is needed for
butalik [34]
The answer is C, a catalyst. This is due to the fact that catalysts are substances that can be used to speed up a reaction by lowering the activation energy required. However, the catalyst itself is not actually used up during the reaction.
8 0
3 years ago
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