Answer: The pressure of the He is 2.97 atm
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
Given : 
=total pressure of gases = 6.50 atm
= partial pressure of Nitrogen = 1.23 atm
= partial pressure of oxygen = 2.3 atm
= partial pressure of Helium = ?
putting in the values we get:
The pressure of the He is 2.97 atm
Answer:
872.28 kJ/mol
Explanation:
The heat released is:
ΔH = C*ΔT
where ΔH is the heat of combustion, C is the heat capacity of the bomb plus water, and ΔT is the rise of temperature. Replacing with data:
ΔH = 9.47*5.72 = 54.1684kJ
A quantity of 1.922 g of methanol in moles are:
moles = mass / molar mass
moles = 1.992/32.04 = 0.0621 mol
Then the molar heat of combustion of methanol is:
ΔH/moles = 54.1684/0.0621 = 872.28 kJ/mol
The total mass is 10.57+6.96=17.53 g.
So, the percent by mass of magnesium is (10.57)/(17.53) * 100 = <u>60.3%</u>
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The percent by mass of oxygen is (6.96)/(17.53) * 100 = <u>39.7%</u>
Explanation:
The given chemical equation is:
The rate of the reaction is 0.0352 M/s.
During the course of the reaction, the rate of reactants decreases, and the rate of products increases.
The rate of disappearance of B is shown below:
![rate=-\frac{1}{4} \frac{d[B]}{dt}](https://tex.z-dn.net/?f=rate%3D-%5Cfrac%7B1%7D%7B4%7D%20%5Cfrac%7Bd%5BB%5D%7D%7Bdt%7D)
So, rate of change of B is :
Option C.
Answer:
24 moles of oxygen are required.
Explanation:
Given data:
Number of moles of CuFeS = 12 mol
Number of moles of O₂ react = ?
Solution:
Chemical equation:
2CuFeS + 4O₂ → Cu₂S + 3SO₂ + 2FeO
now we will compare the moles of O₂ and CuFeS.
CuFeS : O₂
2 : 4
12 : 4/2×12 = 24 mol
