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Zanzabum
3 years ago
6

Say you dropped a cannonball from the 17–meter mast of a ship sailing at 2 meters/second. How far from the base of the mast will

the ball land?
Physics
1 answer:
vichka [17]3 years ago
3 0
It should land at the base of the mast. the cannonball, whilst in your hand, is travelling at the same rate as the boat in the horizontal plane ie at 2m/s. as it leaves you hand it should retain that velocity and therefore land right underneath where it was dropped. this assumes all other things are equal, eg there is no air resistance etc that might cause the ball to accelerate or decelerate.
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Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that ap
Anna11 [10]

Answer:

. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph

5 0
3 years ago
A solar flare is a sudden, rapid, and intense change in the brightness of the sun. Which of these is most
nikdorinn [45]

Answer:

electronic communications may be disrupted

Explanation:

Solar Flares: They occur when the magnetic field lines carrying charged particle entangle and reorganize over the photosphere of the Sun. In these flares charged particles leave the surface of the Sun to travel outwards.

If these flares are directed towards Earth, they will interact with anything related to electricity and magnetism. Out of the given options third option is correct as the electronic communication will be disrupted. If the flares are strong a complete power blackout may occur and that would disrupt all the communication channel and power transmission. Such events have occurred in the past as well.

8 0
3 years ago
A car (mass = 1200 kg) is traveling at 31.1 m/s when it collides head-on with a sport utility vehicle (mass = 2830 kg) traveling
IrinaVladis [17]

Answer:

13.18 m/s

Explanation:

Let the velocity of sports utility car is

-u as it is moving in opposite direction.

mc = 1200 kg, uc = 31.1 m/s

ms = 2830 kg, us = - u = ?

Using conservation of momentum

mc × uc + ms × us = 0

1200 × 31.1 - 2830 × u = 0

u = 13.18 m/s

4 0
3 years ago
An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. What is the minimum coef
navik [9.2K]

An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. The minimum coefficient of static friction needed for this claim to be possible is 0.7

In an inclined plane, the coefficient of static friction is the angle at which an object slide over another.  

As the angle rises, the gravitational force component surpasses the static friction force, as such, the object begins to slide.

Using the Newton second law;

\sum F_x = \sum F_y = 0

\mathbf{mg sin \theta -f_s= N-mgcos \theta = 0 }

  • So; On the L.H.S

\mathbf{mg sin \theta =f_s}

\mathbf{mg sin \theta =\mu_s N}

  • On the R.H.S

N = mg cos θ

Equating both force component together, we have:

\mathbf{mg sin \theta =\mu_s \ mg \ cos \theta}

\mathbf{sin \theta =\mu_s \ \ cos \theta}

\mathbf{\mu_s = \dfrac{sin \theta }{ cos \theta}}

From trigonometry rule:

\mathbf{tan \theta= \dfrac{sin \theta }{ cos \theta}}

∴

\mathbf{\mu_s =\tan \theta}}

\mathbf{\mu_s =\tan 35^0}}

\mathbf{\mu_s = 0.700}}

Therefore, we can conclude that the minimum coefficient of static friction needed for this claim to be possible is 0.7

Learn more about static friction here:

brainly.com/question/24882156?referrer=searchResults

8 0
3 years ago
How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s2
soldier1979 [14.2K]
∑F = ma = (90 kg)(1.2 m/s²) = 108 N = 100 N (1 significant digit)

3 0
3 years ago
Read 2 more answers
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