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Sunny_sXe [5.5K]
3 years ago
7

Jocelyn got 19 correct answers out of 25 questions on her last test . what percent of the questions did she answer correctly

Mathematics
1 answer:
aleksandrvk [35]3 years ago
4 0
19 ÷ 25= 0.76

0.76 ⇒ 76%
She got a C on the test.

Hoped this helped.

~Bob Ross®
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Plz help me with this
Artemon [7]

Answer:

C Is the corect answer

Step-by-step explanation:

Brcause you multiple the 4 and 8 = 38

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6 0
3 years ago
If US=52, ST=30, UT=40, VW=27, and XW=36, find the perimeter of ΔVWX. Round your answer to the nearest tenth if necessary. Figur
Ierofanga [76]

Answer:

The perimeter is 109.8

Step-by-step explanation:

As we can see here, the angles of the triangles are congruent so we can say that both triangles are congruent

When two triangles are congruent, the ratio of their corresponding sides are equal

So we can get the scale factor here by looking at the sides facing each specific angle in both triangles

In the bigger triangle,

The side facing 34 degrees has a length of 30

In the smaller triangle,

The side facing 34 degree has a length of 27

So the scale factor to get the smaller from the bigger is 27/30 = 9/10 or 0.9

Likewise the side facing 51 degrees in the bigger is 40 while for the smaller, it is 36

So the ratio still stands at 36/40 = 9/10 or 0.9

In essence, the smaller triangle will have a perimeter that is 0.9 times that of the bigger

The perimeter of the bigger is simply the sum of the side lengths

We have this as;

(52 + 30 + 40) = 122

so that of the smaller would be;

122 * 0.9 = 109.8

3 0
3 years ago
PLEASE HELP! Will mark Brainliest!
arlik [135]
Circle A would make more sense (I'm not exactly sure) because it shows the entire circle (if you know what I mean).
7 0
3 years ago
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Aliun [14]
5. Line e and line c
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3 0
3 years ago
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How do you do this and what’s the answer to this I been stuck on this question for litterly 20 mins
Vsevolod [243]

\bf T=2\pi \sqrt{\cfrac{L}{g}}\implies \stackrel{\textit{squaring both sides}}{(T)^2=\left( 2\pi \sqrt{\cfrac{L}{g}}\ \right)^2}\implies T^2=2^2\pi^2\sqrt{\left( \cfrac{L}{g} \right)^2} \\\\\\ T^2=4\pi^2\cfrac{L}{g}\implies T^2=\cfrac{4\pi^2L}{g}\implies gT^2=4\pi^2L\implies g=\cfrac{4\pi^2L}{T^2}

6 0
3 years ago
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