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Juli2301 [7.4K]
3 years ago
15

The potential energy of a pair of hydrogen atoms separated by a large distance .x is given by L/(x) = —C6/x6, where C6 is a posi

tive constant. What is the force that one atom exerts on the other? Is this force attractive or repulsive?
Physics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

Explanation:

The force that one atom exerts on the other is the negative derivative of the potential energy = \frac{-dL(x)}{dx}

F(x) = - \frac{d}{dx}( -C₆ / x⁷) = - (- (-6) C₆ x⁻⁶ ⁻¹) = - 6C₆ /x⁷

when xis negative, F is positive and when x is positive, F is negative. It is therefore and attractive force and F is always directed to the center

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Using Excel, or some other graphing software, plot the values of y as a function of x. (You will not submit this spreadsheet. Ho
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Answer:

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Call:

lm(formula = y ~ x)

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And the output is given by:

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Part b

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And if we compare this with the general model y = mx +b

We see that the slope is m= 0.98 and the intercept b = 1.10

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3 years ago
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