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Juli2301 [7.4K]
3 years ago
15

The potential energy of a pair of hydrogen atoms separated by a large distance .x is given by L/(x) = —C6/x6, where C6 is a posi

tive constant. What is the force that one atom exerts on the other? Is this force attractive or repulsive?
Physics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

Explanation:

The force that one atom exerts on the other is the negative derivative of the potential energy = \frac{-dL(x)}{dx}

F(x) = - \frac{d}{dx}( -C₆ / x⁷) = - (- (-6) C₆ x⁻⁶ ⁻¹) = - 6C₆ /x⁷

when xis negative, F is positive and when x is positive, F is negative. It is therefore and attractive force and F is always directed to the center

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THIS IS MY EXAM HURRY PLS
tangare [24]

Answer:

elements in the same column have the same number of neutrons. elements with similar mass are placed in the same column.

5 0
2 years ago
Read 2 more answers
A firecracker breaks up into two pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/
larisa [96]

Answer:

Total momentum, p = 21.24 kg-m/s

Explanation:

Given that,

Mass of first piece, m_1=200\ g= 0.2\ kg

Mass of the second piece, m_2=300\ g= 0.3\ kg

Speed of the first piece, v_1=82\ m/s (along x axis)

Speed of the second piece, v_2=45\ m/s (along y axis)

To find,

The total momentum of the two pieces.

Solve,

The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.

p_x=m_1v_1

p_x=0.2\ kg\times 82\ m/s

p_x=16.4\ kg-m/s

p_y=m_2v_2

p_y=0.3\ kg\times 45\ m/s

p_y=13.5\ kg-m/s

The net momentum is given by :

p=\sqrt{p_x^2+p_y^2}

p=\sqrt{16.4^2+13.5^2}

p = 21.24 kg-m/s

Therefore, the total momentum of the two pieces is 21.24 kg-m/s.

4 0
2 years ago
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.10. The mass of the object i
denis-greek [22]

Answer:

Explanation:

1) Force Friction = Normal Force * Coefficient of Friction

Force Friction = Mass * Gravity * Coefficient of Friction

2) F = ma

Force = mass * acceleration

Force Friction (from #1) = mass * acceleration

acceleration = Force Friction / Mass

6 0
2 years ago
A,b,c,d please I don't understand it.
emmasim [6.3K]
For A: LED outdoor lighting.
Because you want it to be able to withstand outdoor conditions. If it can’t withstand... there’s no light... no light... no advertisement.

For B: it would be lithonium lights. It’s found in most offices and gives the best light for working day or night.

For C: you’ll want elevated lights so they are noticed for the plane to land and for people and others to see.

For D: you want white light and you want it to also be able to withstand outdoor conditions. Cars and people need to see at night, especially at night. Solar would be a great choice.

Hope this helps! I tried hard.
7 0
2 years ago
A 13 cm long tendon was found to stretch 3.7 mm by a force of 12.1 N . The tendon was approximately round with an average diamet
liq [111]

Answer:

young's modulus=\frac{stress}{strain}=\frac{0.1990\times 10^{6}}{28.46\times 10^{-3}}=6.99\times 10^6N/m^2

Explanation:

We have given length of tendon L= 13 cm =0.13 m

Change in length \Delta L=3.7mm=3.7\times 10^{-3}m

Force = 12.1 N

Average diameter d =8.8 mm

So r=\frac{d}{2}=\frac{8.8}{2}=4.4mm=4.4\times 10^{-3}m

Area A=\pi\times  (4.4\times 10^{-3})^2=60.79\times 10^{-6}m^2

Now stress =\frac{force}{area}=\frac{12.1}{60.79\times 10^{-6}}=0.1990\times 10^6N/m^2

Strain =\frac{change\ in\ lenght}{length}=\frac{3.7\times 10^{-3}}{0.13}=28.46\times 10^{-3}

Now young's modulus=\frac{stress}{strain}=\frac{0.1990\times 10^{6}}{28.46\times 10^{-3}}=6.99\times 10^6N/m^2

8 0
3 years ago
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