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Leni [432]
3 years ago
8

How many protons do you think are dissociable from propionic acid and butyric acid? Explain your reasoning.

Chemistry
1 answer:
RSB [31]3 years ago
7 0

Answer:

One

Explanation:

The formulas for the two acids are CH₃CH₂COO-H and CH₃CH₂CH₂COO-H.

The key factors to consider are the polarities of the C-H and O-H bonds.

A. C-H bonds

The difference in electronegativity is ΔEN =|2.55 - 2.20| = 0.35.

This difference of so small that we usually consider the C-H bond to be nonpolar.

It is extremely unlikely that a C-H bond will dissociate onto ions.

B. O-H bonds

The difference in electronegativity is ΔEN =|3.44 - 2.20| = 1.24.

Thus, an O-H bond is highly polar covalent — the bond has about 32 % ionic character.

It is much more likely that an O-H bond will go all the way and dissociate onto ions.

RCOOH + H₂O ⇌ RCOO⁻ + H₃O⁺

The Kₐ for an O-H bond is about 10⁴⁶ times that of a C-H bond.

Only the O-H bond of a carboxylic acid will dissociate,

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4 years ago
The reactants of two chemical equations are listed.
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Equation 2, because K being more reactive, exchanges position with Pb in PbNO3.

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What is the layer of Earth's atmosphere that has the coldest temperature range?
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3 years ago
If the mass of a material is 109 grams and the volume of the material is 24 cm3, what would the density of the material be? g/cm
MakcuM [25]
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6 0
4 years ago
A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t  1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= \frac{w}{W} = \frac{w}{V}= density

P = \frac{density RT}{M}       density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = \frac{0.525 x 0.0821 x 608.15 }{M}

  M    = 34.61

         

to calculate the Kc

Kc=\frac{ [NO] [O2]}{NO2}

  \frac{1-2x}{1+x} x M NO2 + \frac{2x}{1+x} M NO+ \frac{x}{1+x} M O2

Putting the values as molecular weight of NO2, NO,O2

\frac{46(1-2x) +30(2x)+32x}{1+x}

34.61= \frac{46}{1+x}

x= 0.33

Kc= \frac{4x^2)x}{1-2x^2}

    putting the values in the above equation

Kc = 0.00662

     

5 0
3 years ago
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