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ohaa [14]
3 years ago
10

Aluminum metal reacts with aqueous iron(III) oxide to form aqueous aluminum oxide and iron metal. What is the stoichiometric coe

fficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients
Chemistry
1 answer:
Svetach [21]3 years ago
6 0

Answer:

The stoichiometric coefficient for aluminum is 2

Explanation:

Step 1: Data given

Aluminum metal = Al(s)

aqueous iron(III) oxide = Fe2O3(s)

aqueous aluminum oxide  = Al2O3(s)

iron metal = Fe(s)

Step 2: The unbalanced equation

Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)

Step 3: Balancing the equation

On the left side we have 1x Al , on the right we have 2x Al (in Al2O3). To balance the amount of Al on both sides, we have to multiply Al (on the left side) by 2.

2Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)

On the left side we have 2x Fe (in Fe2O3) , on the right we have 1x Fe. To balance the amount of Fe on both sides, we have to multiply Fe (on the right side) by 2. Now the equation is balanced.

2Al(s) + Fe2O3(s) → Al2O3(s) +2Fe(s)

The stoichiometric coefficient for aluminum is 2

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How many atoms are present in a sample of Potassium (K) weighing 33.49g?
madam [21]

Answer:

5.158 × 10²³ atoms K

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

33.49 g K

<u>Step 2: Identify Conversions</u>

Avogadro's Number

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<u>Step 3: Convert</u>

<u />33.49 \ g \ K(\frac{1 \ mol \ K}{39.10 \ g \ K} )(\frac{6.022 \cdot 10^{23} \ atoms \ K}{1 \ mol \ K} ) = 5.15797 × 10²³ atoms K

<u>Step 4: Check</u>

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