An element from Group 2 will form ionic bonds with a nonmetal, Groups 13-17
Explanation:
An ionic bond is formed between a "metal and non-metal". The valence electrons are lost in one and gained in the other atom. It involves electrostatic forces between the two ions which are of opposite charges.
When one atom(metal) losses an electron, it becomes a "positive ion". Similarly, when the other atom(non-metal) gains an electron it becomes a negative ion. For example: The formation of NaF(Sodium Fluoride).
Answer:
Chlorine has higher Electron Affinity as compared to Bromine
Explanation:
Electron affinity is defined as the Potential energy change of the atom when an electron is added to a neutral gaseous atom. Therefore, more the Negative electron affinity, more favorable will be the electron addition process.
The electron affinity of Chlorine is -349kJmol^-1
The electron affinity of Bromine is -324.6KJmol^-1
This clearly shows that Chlorine is a much better Atom to be bonded with, That is the reason why in the reaction is not feasible.
→
Therefore, Chlorine has higher electron Affinity as compared to Bromine and that what makes it a much better atom to be bonded with Na. So the above reaction is not possible.
Answer: One mole of lead (Pb) contains 6.02 × 1023 atoms and its mass is 207.2 g.
Explanation: please give me brainlist. i haven't been brainlist in a while. even my zodiac sign is ♓
Calcium forms an ionic bond to iodine and forms calcium iodide (CaI2). The calcium atom gives away 2 of its valence electrons, one to each of the 2 iodine atoms thus forming the ionic bond.
<span>Chemical reactivity of all of the different elements in the periodic table depends on the number of electrons in that last, outermost level, called the valence level or valence shell. In the case of gold, there is only </span>one valence electron<span> in its valence level. Hope I helped! :)</span>