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Orlov [11]
3 years ago
9

20 Points!!!!!!!!!!!! Please Help!!!!

Chemistry
2 answers:
mrs_skeptik [129]3 years ago
5 0
#1 is actually C.. Carrying Capacity is the population size an environment can sustain. Thats what my study guide says. <span />
mamaluj [8]3 years ago
3 0
Number 1: (A.)
Number 2: (A.)
Number 3: (B.)

I'm probably wrong but that is what i think
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For the balanced equation shown below, how many moles of O2 will react with 0.3020 moles of CO2?
andrezito [222]
Answer is: 0,453 <span> moles of oxygen will react </span><span>with 0.3020 moles of carbon(IV) oxide</span><span>.
</span>n(CO₂) = 0,302 mol.
From chemical reaction: n(CO₂) : n(O₂) = 4 : 6.
n(O₂) = 6 · 0,302 mol ÷ 4.
n(O₂) = 0,453 mol.
n - amount of substance.
6 0
3 years ago
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Explain the following terms Sublimation
weqwewe [10]

Answer:

Sublimation is the transition of a substance directly from the solid to the gas state, without passing through the liquid state. ... The reverse process of sublimation is deposition or desublimation, in which a substance passes directly from a gas to a solid phase.

8 0
3 years ago
From left to right, the three regions of a phase diagram represent the _____ of a substance.
timofeeve [1]
Your answer is D.


:good luck

5 0
3 years ago
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Helpppppppppp!!!!!!!!!​
professor190 [17]

Answer:

a

Explanation:

the solution is extremely acidic and will dissolve the zinc rod

3 0
3 years ago
An oxybromate compound, kbrox, where x is unknown, is analyzed and found to contain 43.66 % br.
aniked [119]

Answer is: an oxybromate compound is KBrO₄ (x = 4).

ω(Br) = 43.66% ÷ 100%.

ω(Br) = 0.4366; mass percentage of bromine.

If we take 100 grams of compound:

m(Br) = ω(Br) · 100 g.

m(Br) = 0.4366 · 100 g.

m(Br) = 43.66 g; mass of bromine.

n(Br) = m(Br) ÷ M(Br).

n(Br) = 43.66 g ÷ 79.9 g/mol,

n(Br) = 0.55 mol; amoun of bromine.

From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).

m(K) = 0.55 mol · 39.1 g/mol.

m(K) = 21.365 g; mass of potassium in the compound.

m(O) = 100 g - 21.365 g - 43.66 g.

m(O) =34.97 g; mass of oxygen.

n(O) = 34.97 g ÷ 16 g/mol.

n(O) = 2.185 mol.

n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.

n(K) : n(Br) : n(O) = 1 : 1 : 4.

6 0
3 years ago
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