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maria [59]
3 years ago
7

Which explains why the ratio of cell surface area to volume affect the cell size? PLEASE HELP ASAP! THIS IS DUE TOMORROW!

Chemistry
1 answer:
diamong [38]3 years ago
5 0
Think about it this way: a cell can only take in materials through the cell membrane. Naturally, as the cell membrane surface area increases, then the amount of material that can enter the cell increases due to more entry points along the membrane. However, when the cell increases in size then the volume inside the cell will also increase - more volume inside requires more energy to transport materials around the cell. So, there is a trade-off between the surface area and volume. 
<span>As an example, consider a sphere as a cellular model. The surface area of a sphere is </span>

<span>SA = 4*pi*r^2 </span>

<span>while the volume of the sphere is </span>

<span>V = 4/3*pi*r^3 </span>

<span>initially, as a very small cell increases in radius, the surface area will increase at a greater rate than the volume. But as the cell gets bigger there will be a point where the volume increases faster than the surface area. Cells have maximized this ratio through evolution (this is also one reason why we are not single-celled organisms). </span>
<span>Some cells are able to get around this issue to some extent by "folding" the membrane, thus increasing the surface area without affecting the volume by much. </span>
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Answer:

The following three isomeric structure are given below.

Explanation:

Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂

Ester #1: methyl 1-methylcyclobutanecarboxylate

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Explanation:

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Question 2
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Answer:

1-Pentene

Explanation:

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3 years ago
What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.
Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M

Putting values in above equation, we get:

pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88

Hence, the hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

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