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3 years ago

What type of compounds dissolve easily in water?

Chemistry

2 answers:

Crank3 years ago

6 0

Well you got what th other person or you got nothin lol

Alekssandra [29.7K]3 years ago

5 0

Ionic compound and polar molecule compound

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How many kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten mgcl2 with an appl

ratelena [41]

First, we need to determine the half reaction of magnesium. It would be expressed as:

Mg2+ + 2e- = Mg

Given the mass of magnesium metal that is produced, we calculate the total charge of the electrolysis by the relations we can get from the half reaction. We do as follows:

4.50 kg Mg ( 1000 g / 1 kg ) ( 1 mol / 24.305 g ) ( 2 mol e- / 1 mol Mg ) ( 96500 C / 1 mol e- ) = 35733388.2 C

We are given the applied EMF in units of V. This value is equal to J/C. So, 5 V is equal to 5 J/C.

35733388.2 C (5 J/C) = 178666941 J
178666941 J ( 1 kW-h / 3.6x10^6 J ) = 49.63 kW-h

3 0

3 years ago

Need help with these two pls!!

denis23 [38]

what is a fire piston?

*a tool for starting a fire, likely invented in Ancient Southeast Asia.*

dont know the second one lol.

8 0

3 years ago

Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What nu

vichka [17]

Answer:

Explanation:

Hello,

In this case, it is convenient to write the chemical reaction as:

$CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3$

Which balanced turns out:

$3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3$

Thus the number that should be in front of the calcium sulfate is 3 in order to balance the reaction.

Best regards.

8 0

3 years ago

What did the periodic table help scientists discover?

Monica [59]

They discovered that *elements* show increase in atomic numbers across the period.

8 0

3 years ago

Read 2 more answers

What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi

Tomtit [17]

Answer:

The required volume is 1.6 x 10³mL.

Explanation:

When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:

C₁ . V₁ = C₂ . V₂

where,

C₁ and V₁ are the concentration and volume of the concentrated solution

C₂ and V₂ are the concentration and volume of the dilute solution

In this case, we want to find out V₁:

C₁ . V₁ = C₂ . V₂

$V_{1} = \frac{C_{2}.V_{2}}{C_{1}} = \frac{1.5M \times1.11.10^{4}mL }{10.2M} =1.6\times10^{3} mL$

3 0

3 years ago