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2 years ago

Given the balanced equation representing a reaction:

Chemistry

1 answer:

zloy xaker [14]2 years ago

8 0

Answer:

An acid because they donate H^+ ions

Explanation:

Let us look at the equation again;

H2SO3 + H2O « H3O+ + HSO3-

An acid donates hydrogen ion while a base accepts hydrogen ion. Hence, we have to look at which species that acted as hydrogen ion donors or acceptors.

We can clearly see that H2SO3 acted as a hydrogen ion donor while H2O acted as a hydrogen ion acceptor.

Thus, H2SO3 acted as an acid by donating hydrogen ions.

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Sulfuryl dichloride is formed when sulfur dioxide reacts with chlorine.

zubka84 [21]

<u>Answer:</u> The value of $\Delta G^o$ of the reaction is 28.38 kJ/mol

<u>Explanation:</u>

For the given chemical reaction:

$SO_2(g)+Cl_2(g)\rightarrow SO_2Cl_2(g)$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(SO_2Cl_2(g))})]-[(1\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(Cl_2(g))})]$

We are given:

$\Delta H^o_f_{(SO_2Cl_2(g))}=-364kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H^o_f_{(Cl_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(1\times (-364))]-[(1\times (-296.8))+(1\times 0)]=-67.2kJ/mol=-67200J/mol$

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_f_{(product)}]-\sum [n\times \Delta S^o_f_{(reactant)}]$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(1\times \Delta S^o_{(SO_2Cl_2(g))})]-[(1\times \Delta S^o_{(SO_2(g))})+(1\times \Delta S^o_{(Cl_2(g))})]$

We are given:

$\Delta S^o_{(SO_2Cl_2(g))}=311.9J/Kmol\\\Delta S^o_{(SO_2(g))}=248.2J/Kmol\\\Delta S^o_{(Cl_2(g))}=223.0J/Kmol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(1\times 311.9)]-[(1\times 248.2)+(1\times 223.0)]=-159.3J/Kmol$

To calculate the standard Gibbs's free energy of the reaction, we use the equation:

$\Delta G^o_{rxn}=\Delta H^o_{rxn}-T\Delta S^o_{rxn}$

where,

$\Delta H^o_{rxn}$ = standard enthalpy change of the reaction =-67200 J/mol

$\Delta S^o_{rxn}$ = standard entropy change of the reaction =-159.3 J/Kmol

Temperature of the reaction = 600 K

Putting values in above equation, we get:

$\Delta G^o_{rxn}=-67200-(600\times (-159.3))\\\\\Delta G^o_{rxn}=28380J/mol=28.38kJ/mol$

Hence, the value of $\Delta G^o$ of the reaction is 28.38 kJ/mol

7 0

3 years ago

Choose the aqueous solution below with the highest freezing point. These are all solutions of nonvolatile solutes and you should

GrogVix [38]

Answer:

0.200 m K3PO3

Explanation:

Let us remember that the freezing point depression is obtained from the formula;

ΔTf = Kf m i

Where;

Kf = freezing point constant

m = molality

i = Van't Hoff factor

The Van't Hoff factor has to do with the number of particles in solution. Let us consider the Van't Hoff factor for each specie.

0.200 m HOCH2CH2OH - 1

0.200 m Ba(NO3)2 - 3

0.200 m K3PO3 - 4

0.200 m Ca(CIO4)2 - 3

Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.

8 0

3 years ago

__Pb(NO3)2 + __NaCI = __NaNO3 + __PbCI2

Elena L [17]

Answer:

Pb(NO3)2 + 2NaCl = 2NaNO3 + PbCl2

6 0

1 year ago

A carbene is a highly reactive intermediate in which a carbon atom bears a lone pair and no formal charge: how many hydrogen ato

Colt1911 [192]

Carbene is :CH₂ (i.e, methylene) which contains one neutral divalent carbon atom with valency of two and two unshared valence electrons. Carbene is of two types: Singlet carbene and Triplet carbene. Carbenes are very short lived and unstable. It is highly reactive intermediate. General carbene which refers to specific species methylene ( :CH₂) contains two hydrogen atoms. Carbene is one of the very important intermediate of various organic synthesis.

4 0

3 years ago

One of the products of the combustion reaction below:

Ratling [72]

Answer:

H₂O

Explanation:

Chemical equation:

C₅H₁₂ + O₂ → CO₂ + H₂O

Balanced chemical equation:

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O

The given reaction is combustion reaction. The balance equation shows that there are equal number of moles of carbon, hydrogen and oxygen on both side of equation thus it follows the law of conservation of mass.

Combustion reaction:

The reaction in which substance react with oxygen and produced carbon dioxide and water.

Mostly hydrocarbons burns in the presence of oxygen and form carbon dioxide and water.

6 0

2 years ago