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strojnjashka [21]
3 years ago
12

Given the balanced equation representing a reaction:

Chemistry
1 answer:
zloy xaker [14]3 years ago
8 0

Answer:

An acid because they donate H^+ ions

Explanation:

Let us look at the equation again;

H2SO3 + H2O « H3O+ + HSO3-

An acid donates hydrogen ion while a base accepts hydrogen ion. Hence, we have to look at which species that acted as hydrogen ion donors or acceptors.

We can clearly see that H2SO3 acted as a hydrogen ion donor while H2O acted as a hydrogen ion acceptor.

Thus, H2SO3  acted as an acid by donating hydrogen ions.

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Answer:

carbon dioxide

Explanation:

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What is the answer to 2.5 * 22.5
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Your answer to 2.5*22.56 is 56.25
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If the age of the middle layer of a rock sample is between 600 million years and 1 billion years, which of the following could b
Varvara68 [4.7K]

200 million year to 550 million years old

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. A reaction in which A, B, and C react to form products is first order in A, second order in B, and zero order in C. a) Write a
AleksAgata [21]

Answer:

a) r = k × [A] × [B]²

b) 3

Explanation:

Let's consider the following generic reaction

A + B + C ⇒ Products

The generic rate law is:

r = k × [A]ᵃ × [B]ᵇ × [C]ⁿ

where

  • r: reaction rate
  • k: rate constant
  • a, b, n: reaction orders

This reaction is first order in A, second order in B, and zero order in C. The rate law is:

r = k × [A]¹ × [B]² × [C]⁰

r = k × [A] × [B]²

The overall order of the reaction is the sum of the individual reaction orders.

1 + 2 + 0 = 3

4 0
3 years ago
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
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