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soldier1979 [14.2K]
3 years ago
13

State the Lagrange Theorem, and find the order of all possible subgroups of a group of order 5. The same question of a group of

order 6.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

  Lagrange Theorem

Step-by-step explanation:

The Lagrange Theorem:

Let G be a finite group and T be a subgroup of G. Then the order of T divides the Order of group G.

This can be written as:

If T \subset G, then, o(T)|o(G).

Possible Subgroups

Now, we are given a group with order 5. We have to find all possible subgroups.

So, the possible subgroup are: groups with order 1, group with order 5

We are given a group with order 6.

Possible subgroups are: group of order 1, group of order 2, group of order 3 and group of order 4.

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For all values of x
Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

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5 0
3 years ago
Which equation is equivalent to<br><br> f(x) = 16x4 – 81 = 0?
Vesna [10]

Answer:

The equivalent expression is:

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Step-by-step explanation:

We have been given the equation:

f(x)=16x^4-81=0

Equivalent expression can be computed by solving the expression ai its maximum.

We can factorize the given equation:

By using a^2-b^2=(a+b)(a-b)

Here, a=4x^2,b=9

Hence, we get the equation below:

16x^4-81=(4x^2-9)(4x^2+9)

Therefore, the equivalent expression is:

16x^4-81=(4x^2-9)(4x^2+9)

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7 0
3 years ago
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