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Anastasy [175]
3 years ago
11

22 ------ -2 twenty 2 over negitive 2

Mathematics
2 answers:
sergejj [24]3 years ago
8 0
22/-2 is -11 (divide)
REY [17]3 years ago
3 0
I think it is - 22 
i hope this helps:)

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forsale [732]
Cut 5 equal sections from a 2 foot long ribbond
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4 years ago
A volume of a coin is 113.04 mm2 what is the approximate of a sphere that has the same height and a circular base with the same
tia_tia [17]

We have been given that the volume of a cone is 113.04 cubic mm. We are asked to find the approximate volume of a sphere that has the same height and a circular base with the same diameter.

We know that volume of cone is \frac{1}{3}\pi r^2\cdot h.

The height is equal to the diameter. We know that diameter is 2 times radius, so we can represent this information in an equation as:

h=2r

Upon substituting h=2r in volume of cone, we will get:

V=\frac{1}{3}\pi r^2\cdot 2r

V=\frac{2}{3}\pi r^3

We know that volume of sphere is V=\frac{4}{3}\pi r^3.

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Since \frac{2}{3}\pi r^3=113.04, so volume of sphere would be:

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Therefore, volume of sphere would be 226.08 cubic mm.

4 0
4 years ago
Which graph represents -3x+4>7?
schepotkina [342]
- 3x + 4 \geqslant 7 \\ - 3x \geqslant 3 \\ - x \geqslant 1 \\ x < - 1
The 1st option because needed to flip the inequalities sign when multiplied by a negative.

Hope this helps. - M
7 0
4 years ago
If one class collected 65 cans for the food drive and another class collected 176 cans, how many cans did the two classes collec
kotegsom [21]
In this equation C means the total. In order to find the total you must add the two class together to get the total. The equation that represents this would be the fourth one. 65 + 176 = C
7 0
4 years ago
Read 2 more answers
How do you do this?PLZ HELP
Alisiya [41]
3(x^2+10x+5)-5(x-k)=
3x^2+30x+15-5x+5k=
3x^2+25x+15+5k

for this to be divisible by x every term must include x or get eliminated

the problematic terms are 15 and 5k
to eliminate them they must equal 0 when added:
15+5k=0
5k=-15
k=-3

so A) -3 is the solution
5 0
4 years ago
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