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dangina [55]
3 years ago
10

How many grams of iron(III) oxide would be required to make 187 g of iron

Chemistry
1 answer:
enyata [817]3 years ago
4 0

Answer:267 g

Explanation:

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A sample of gas occupies a volume of 67.5 mL . As it expands, it does 131.0 J of work on its surroundings at a constant pressure
baherus [9]

Answer:

The final volume V2=1.3175L

Explanation:

between work ( w), pressure ( P ) and volume ( V ) is the following:

w=−PΔV

where,

ΔV=V2−V1

It was stated that the gas is expanding, then the work is done by the system and it is of a negative value .

Note that work, should be expressed in 1L⋅atm=101.3J

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

4 0
4 years ago
What is a real life example of beta radiation?
Veseljchak [2.6K]

Answer:

your answer would be : examples such as Thallium-206, Lead-210, & Bismuth-214.

7 0
3 years ago
Real gas expansion in a vacuum is exothermic or endothermic?
lisov135 [29]
I think it is exothermic
3 0
4 years ago
A topaz crystal has an interplanar spacing (d) of 1.36 Å (1 Å =1×10^[−10] m). Calculate the wavelength of the X-ray that should
bija089 [108]

Answer:

7.0*10-11m or 70Å

Explanation:

From Bragg's equation, w=2dsinx/n

Since all the parameters are specified in the question, we can easily go ahead to obtain the wavelength but we must convert the spacing given in angstroms to meters using the conversion factor provided as shown in the solution below:

7 0
3 years ago
A 2.026g sample of a hydrate of sodium carbonate (Na2CO3) is heated to remove water. After heating, the mass of the sample is 0.
OLEGan [10]

Answer:

62.98 % of the sample of hydrate is water

Explanation:

Step 1: Data given

Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams

After heating, the mass of the sample is 0.750 g

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mass of water

Mass water = mass of hydrate - mass of sample after heating

Mass water = 2.026 grams - 0.750 grams

Mass water = 1.276 grams

Step 3: Calculate mass % percent of water

Mass % of water = (mass of water / total mass hydrate) * 100 %

Mass % of water = (1.276 grams / 2.026 grams) *100 %

Mass % of water = 62.98 %

62.98 % of the sample of hydrate is water

7 0
3 years ago
Read 2 more answers
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