I need help with how to solve this problem. It is #14. It already shows the answer (1point) but I need help on how to get there
please.
1 answer:
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Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:
Rewrite the integrand:
The integral is then
A ) A function representing the amount of the dose that remains:
B ) Graph is in the attachment.
C ) f ( 10 ) = 10 * ( 0.95 ) ^10 = 10 * 0.5987 = 5.987 ≈ 6
Answer:
D ) f ( x ) = 10 ( 0.95 ) x; about 6 units.
B ) Graph is in the attachment.
C ) f ( 10 ) = 10 * ( 0.95 ) ^10 = 10 * 0.5987 = 5.987 ≈ 6
Answer:
D ) f ( x ) = 10 ( 0.95 ) x; about 6 units.