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3 years ago

What's the difference between incomplete dominance and codominance

1 answer:

7 0

In total dominance, the phenotype sees only one allele in the genotype. Both alleles in the genotype are seen in the phenotype during codominance. In incomplete dominance, in the phenotype, a mixture of the alleles in the genotype is seen.

You might be interested in

Express the quantity 24.2×10-5 m in mm. express your answer using three significant figures.

sergiy2304 [10]

I think you meant 2.42*10^-6
Remember, the first digit must be between 1 and 10 or - 1 and - 10.
(2.42*10^-6)(1000)
=0.242mm

3 0

3 years ago

Round the following answer correctly. 5.40m x 3.21m x 1.871m = 32.431914 m^3

Klio2033 [76]

The answer is 32.43 because when you round the number next to the hunthers place (witch in this problem would be the 1) has to be 5 or hight to raise the number to the left of it and if it is lower you just take the two number and that is your answer.

5 0

3 years ago

How many moles of methane are in 7.31*10^25 molecules?

GrogVix [38]

<h3>Answer:</h3>

121 mol CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Organic</u>

Writing chemical compounds
Writing organic structures
Prefixes
Alkanes, Alkenes, Alkynes

<u>Atomic Structure</u>

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.31 × 10²⁵ molecules CH₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u /> $\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4$ <u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

121.388 mol CH₄ ≈ 121 mol CH₄

7 0

3 years ago

Boron has two naturally occurring isotopes; B-10 with a mass of 10.01 amu and a natural abundance of 20.00%, and B-11 with a mas

balandron [24]

Atomic mass of boron = 10.81

<h3>What are Isotopes?</h3>

Isotopes are variants of a particular element in which they have the same number of protons but differ in the number of neutrons in the atom.

So, here as we said we have isotopes which weigh 10.01 and 11.01.

Given,

relative abundance of B-10 = 10.1 amu

relative abundance of B- 11 = 11.01 amu

percentage of B-10 = 20%

percentage of B-11 = 80%

Then the relative atomic mass depends upon the relative abundance of various isotopes of that particular element. Suppose an element consists of two isotopes and average atomic mass is equal to

(Relativeabundance(1)×Atomicmass(1)+Relativeabundance(2)×Atomicmass(2)) / (Relativeabundance(1)+Relativeabundance(2))

Atomic mass of boron = (20 × 10.01 + 80 × 11.01) / (80 + 20 )

= 1081/100

= 10.81

To learn more about atomic mass from the given link

brainly.com/question/3187640

#SPJ4

8 0

2 years ago

Why does copper oxide not dissolve in water?

Aliun [14]

Copper oxide<span> is a base because it will react with acids and neutralise them, but it is</span>not<span> an alkali because it </span>does not dissolve in water. Sodium hydroxide is a base because it will react with acids and neutralise them. It's also an alkali because itdissolves in water<span>.</span>

6 0

3 years ago