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Setler79 [48]
3 years ago
12

Which of the following describes what occurs as a gas becomes a liquid?

Chemistry
1 answer:
lora16 [44]3 years ago
5 0
As the gas cools it condenses and becomes a liquid its atoms also become smaller
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Why is partial pressure of oxygen greater at lower levels in water.
saw5 [17]

Answer:

Therefore, the partial pressure of oxygen at high altitudes is less than at sea level.

Explanation:

The deep ocean thus has higher oxygen because rates of oxygen consumption are low compared with the supply of cold, oxygen-rich deep waters from polar regions. In the surface layers, oxygen is supplied by exchange with the atmosphere.

5 0
3 years ago
I NEED HELP PLEASE, THANKS!
Crazy boy [7]

Answer:

Here's what I get.

Explanation:

1. Brønsted-Lowry theory

An acid is a substance that can donate a proton to another substance.

A  base is a substance that can accept a proton from another substance.

2. pH of ammonia

The chemical equation is

\rm NH$_{3}$ + \text{H}$_{2}$O \, \rightleftharpoons \,$ NH$_{4}^{+}$ + \text{OH}$^{-}$

For simplicity, let's re-write this as

\rm B + H$_{2}$O \, \rightleftharpoons\,$ BH$^{+}$ + OH$^{-}$

(a) Set up an ICE table.

                     B + H₂O ⇌ BH⁺ + OH⁻

I/mol·L⁻¹:     0.335             0        0

C/mol·L⁻¹:       -x                +x       +x

E/mol·L⁻¹:  0.335 + x          x         x

\rm K_{\text{b}} = \dfrac{\text{[BH}^{+}]\text{[OH}^{-}]}{\text{[B]}} = 1.8 \times 10^{-5}\\\\\dfrac{x^{2}}{0.335 - x} = 1.8 \times 10^{-5}

Check for negligibility:

\dfrac{0.335}{1.8 \times 10^{-5}} = 28 000 > 400\\\\x \ll 0.335

(b) Solve for [OH⁻]

\dfrac{x^{2}}{0.335} = 1.8 \times 10^{-5}\\\\x^{2} = 0.335 \times 1.8 \times 10^{-5}\\x^{2} = 6.03 \times 10^{-6}\\x = \sqrt{6.03 \times 10^{-6}}\\x = \text{[OH]}^{-} = \mathbf{2.46 \times 10^{-3}} \textbf{ mol/L}

(c) Calculate the pOH

\text{pOH} = -\log \text{[OH}^{-}] = -\log(2.46 \times 10^{-3}) = 2.61

(d) Calculate the pH

pH = 14.00 - pOH = 14.00 - 2.61 = 11.39

3 0
4 years ago
What is the Ka of a 0.0326 M solution of hydrofluoric acid with a pH of 3.94?
LenKa [72]

Answer:

Kₐ = 4.06 × 10⁻⁷

Explanation:

Step 1. <em>Calculate [H₃O⁺] </em>

\text{H}_{3}\text{O}^{+} = 10^{\text{-pH}}\text{ mol/L}

pH = 3.94

\text{H}_{3}\text{O}^{+} = 10^{-3.94}} \text{ mol/L}

[H₃O⁺] = 1.15 × 10⁻⁴ mol·L⁻¹

Calculate K_{\text{a}}

                             HF + H₂O ⇌          H₃O⁺          +          F⁻

I/mol·L⁻¹:           0.0326                          0                         0

C/mol·L⁻¹: 0.0326-1.15 × 10⁻⁴        +1.15 × 10⁻⁴           +1.15 × 10⁻⁴

E/mol·L⁻¹:         0.0325                    1.15 × 10⁻⁴            1.15 × 10⁻⁴

So, at equilibrium,

[H₃O⁺] = [F⁻] = 1.15 × 10⁻⁴ mol·L⁻¹

[HF] = 0.326 – 1.15 × 10⁻⁴  mol·L⁻¹ = 0.0325 mol·L⁻¹

Kₐ = {[H₃O⁺][F⁻]}/[HF]

Kₐ = (1.15 × 10⁻⁴ × 1.15 × 10⁻⁴)/0.0325

Kₐ = 1.32 × 10⁻⁸/0.0325

Kₐ = 4.06 × 10⁻⁷

This is <em>NOT</em> a solution of HF (Kₐ = 7.2 × 10⁻⁴). It is more likely a solution of carbonic acid (H₂CO₃; Kₐ₁ = 4.27 × 10⁻⁷).

8 0
3 years ago
How do the shapes and volumes of solids,liquids, and gases differ?​
fiasKO [112]

Solids have a solid, fixed shape, while liquids can change shape as they are put into a different container or cup. Gases also take the shape of the object they are in.

5 0
4 years ago
Read 2 more answers
A sample that weighs 107.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the samp
My name is Ann [436]
30% of 107.75 g is 32.325g so there are about 8.08125 mol of He which is
4.86 x 10^24 particles
70% of 107.75 g is 75.425g so there are about .9 mol of Kr which is 
5.42 x 10^23 paticles
In the whole sample, there are about 5.41 x 10^24 particles

7 0
3 years ago
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