Which type of mixture can be separated using a sieve?

How many kilojoules of heat are released when 32.0 g of NaOH are dissolved in water? (The molar heat of solution of NaOH is –445

Katen [24]

The energy release when dissolving 1 mol of NaOH in water is 445.1 kJ
the mass of NaOH to be dissolved is 32.0 g
The number of NaOH moles in 32.0 g - 32.0 g / 40 g/mol = 0.8 mol
the energy released whilst dissolving 1 mol of NaOH - 445.1 kJ
when dissolving 0.8 mol - the energy released is 445.1 kJ/mol x 0.8 mol
therefore heat released is - 356.08 kJ
answer is -356.08 kJ

6 0

3 years ago

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2 moles of a gas have a pressure of 2 atm at a temperature of 300 K. What is the volume of the gas?

qwelly [4]

No of moles=2mol=n
Pressure=2atm=P
Temperature=300K=T
Volume=V

$\\ \tt\hookrightarrow PV=nRT$

$\\ \tt\hookrightarrow V=\dfrac{nRT}{P}$

$\\ \tt\hookrightarrow V=\dfrac{2(8.314)(300)}{2}$

$\\ \tt\hookrightarrow V=8.314(300)$

$\\ \tt\hookrightarrow V=2494.2mL$

$\\ \tt\hookrightarrow V=24.94dm^3$

4 0

2 years ago

Can you compare the function of veins in plants with anything else you know.

Veseljchak [2.6K]

hope it helps

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7 0

3 years ago

A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

kupik [55]

hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.

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6 0

2 years ago

HELPP PLEASE!!! :)))))

Murljashka [212]

J. Because birds swim and fish don’t

4 0

2 years ago