Answer:
Work done is 50.4J.
Explanation:
The work
done by the student in lifting the book 1.2 meters vertically is


When the student begins to walk horizontally, the net force on the book is zero <em>(gravity is pulling it down, the student is lifting it up)</em>. Thus, although the student is displacing the book horizontally, but because no force is exerted on it, the work done is zero.
Answer:
11.85m
Explanation:
For the development of this problem we must resort to the concepts of the basic kinematic equations that define the distance of a body, such as speed for a certain time, that is,

From the information provided we say that the distance between the cretas is 0.6m,

In our information we have also that the length between the first and latest wave is in time terms of 2.2s. They are 4 waves in 3 intervals then




Then the distance from the shore is given by the speed of the waves for the total time. That is



Answer: 10 m/s
We're told the speed is constant, so it's not changing throughout the time period given to us. So throughout the entire interval, the speed is 10 m/s.
Answer:
86605.08 N
Explanation:
The equation to calculate the force is:
Force = mass * acceleration
The force and the acceleration does not have the same direction in this case, so we need to decompose the force into its horizontal component, which is the force that will generate the horizontal acceleration:
Force_x = Force * cos(30)
Then, we have that:
Force_x = mass * acceleration
Force * cos(30) = 25000 * 3
Force * 0.866 = 75000
Force = 75000 / 0.866 = 86605.08 N