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3 years ago

14

A chemical lab isolates a gaseous element from the atmosphere that does not form chemical compounds. In which group of the perio

dic table is this element most likely found?
A. 18

B. 17

C. 1

D. 2

1 answer:

Sholpan [36]3 years ago

8 0

Answer:

A- 18

Explanation:

It wont let me explain how

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A bullet of mass 0.02 kg is fired by a gun of mass 20 kg. If the speed of the bullet is 150 ms -1,

wel

Answer:

0.15m/s

Explanation:

Momentum p = mv, must be conserved if there are no external forces acting on the system. Since there are only internal forces acting between the bullet and the gun, momentum must be conserved.

The total momentum before the gun is fired:

$p = m_{bullet}v_{bullet} + m_{gun}v_{gun} = 0.02 * 0 + 20 * 0 = 0$

The total momentum after the gun is fired, must also be zero:

$p = m_{bullet}v_{bullet} + m_{gun}v_{gun} = 0.02 * 150 + 20 * v_{gun} = 0$

Solving for v:

$v_{gun}=-\frac{m_{bullet}v_{bullet}}{m_{gun}} = -\frac{0.02*150}{20} =-0.15$

The recoil speed is the absolute value of the velocity.

7 0

3 years ago

A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is 0.50 μA. H

Nataly_w [17]

I = 5*10 - 7A

q = 5 *15*1- - 7 cuolomb
= 75 *10 -7 C in 15 sec is indecent

1 proton has q = 1.6 *10 - 19C

75 *10-7 / 16* 10-19

= 4.7 x 10^13

Hope this helps

3 0

3 years ago

A proton enters a uniform magnetic field of strength 2 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’

sattari [20]

Answer:

Magnetic force, $F=9.6\times 10^{-17}\ N$

Explanation:

It is given that,

Magnetic field, B = 2 T

Velocity of the proton, v = 300 m/s

Charge on the proton, $q=1.6\times 10^{-19}\ C$

The magnetic field is oriented perpendicular to the proton’s velocity. The magnetic force on the charged particle is given by :

$F=qvB\ sin\theta$

The magnetic field is oriented perpendicular to the proton’s velocity, $\theta=90^{\circ}$

$F=1.6\times 10^{-19}\times 300\times 2$

$F=9.6\times 10^{-17}\ N$

So, the magnitude of the force that the proton experiences while it moves through the magnetic field is $9.6\times 10^{-17}\ N$ . Hence, this is the required solution.

7 0

3 years ago

You raise a bucket of water from the bottom of a deep well. if your power output is 138 w , and the mass of the bucket and the w

inn [45]

Maybe 34.5

I'm not quite sure

8 0

4 years ago

What is the distance covered in 20 minutes by a train traveling 500m/m?

MrMuchimi

Answer:

answer is 10km

Explanation:

use "S =Ut "

S=distance U=velocity t =time

no need to convert time into seconds as the velocity has given in meters per minute

3 0

4 years ago