Animals have a food chain. (sorry for my bad English)
A few different ways to do this:
Way #1:
The current in the series loop is (12 V) / (total resistance) .
(Turns out to be 2 Amperes, but the question isn't asking for that.)
In a series loop, the current is the same at every point, so it's
the same current through each resistor.
The power dissipated by a resistor is (current)² · (resistance),
and the current is the same everywhere in the circuit, so the
smallest resistance will dissipate the least power. That's R1 .
And by the way, it's not "drawing" the most power. It's dissipating it.
Way #2:
Another expression for the power dissipated by a resistance is
(voltage across the resistance)² / (resistance) .
In a series loop, the voltage across each resistor is
[ (individual resistance) / (total resistance ] x battery voltage.
So the power dissipated by each resistor is
(individual resistance)² x [(battery voltage) / (total resistance)²]
This expression is smallest for the smallest individual resistance.
(The other two quantities are the same for each individual resistor.)
So again, the least power is dissipated by the smallest individual resistance.
That's R1 .
Way #3: (Einstein's way)
If we sat back and relaxed for a minute, stared at the ceiling, let our minds
wander, puffed gently on our pipe, and just daydreamed about this question
for a minute or two, we might have easily guessed at the answer.
===> When you wire up a battery and a light bulb in series, the part
that dissipates power, and gets so hot that it radiates heat and light, is
the light bulb (some resistance), not the wire (very small resistance).
The velocity, frequency and wavelength of a wave are related by:
v = fλ
v = 32 x 0.5
v = 16 m/s
The answer is B.
Answer:
Explanation:
Given that,
Height of hill is 50m
Coefficient of friction is μ=0.62
Energy is conserved, then
K.E at the bottom of the hill is equally to P.E at the top of the hill
½mv²=mgh
Mass cancel out
½v²=gh
v²=2gh
v=√2gh
Since g=9.81 and h=50
v=√2×9.81 ×50
v=31.32m/s
This is the initial speed at the bottom of the hill
At the bottom of the hill 3 forces are acting on the body
1. Weight,
2. Normal
3. Frictional force
Now taking newton law of motion
ΣF = ma.
Along y axis, since the body is not moving in y direction, they acceleration along y is 0m/s²
ΣFy = 0
N-W=0
N=W
Since weight =mg
N=W=mg
Using law of friction, Fr=μN
Therefore,
Fr=μmg
Applying Newton law to the x-direction
ΣFx = ma
Fr=ma,
Since Fr=μ mg
μ mg=ma
a=μg
Given that μ=0.62 and g=9.81
a=0.62×9.82
a=6.076m/s²
Since we have acceleration, we can use any of the equation of motion to find distance travel
v²=u²-2gS, . this is due that the box is decelerating and it comes to a halt and this show that final velocity v=0m/s
Then,
0²=31.32²-2×9.81 ×S
-31.32² =-2×9.81×S
S=31.32²/(2×9.81)
S=50.05m
The sled will travel a distance of 50.1m once it reach the bottom
Answer:
true
Explanation:
dbgkdodocofkci ifkdcl k kfododocp v
, is related to the speed of the wave in the medium by the relation: