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3 years ago

The defense is the team that is trying to score a goal. A. True B. False

Physics

2 answers:

Stolb23 [73]3 years ago

7 0

The defense is the team that is trying to score a goal. False

larisa86 [58]3 years ago

5 0

Answer:

true

Explanation:

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When electricity is produced from coal, the chemical energy in<br> coal iS changed to<br> energy.

WINSTONCH [101]

Answer:

love

Explanation:

6 0

3 years ago

Do all of them please and explain

kondaur [170]

At 305 and 309 it was negative because it is going down

at 300 and 301 and 305 it was positive because its going up

at 302/303/304/306/309 she wasn't accelerating at all because it is staying the same

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3 years ago

Read 2 more answers

3.12 ** To illustrate the use of a multistage rocket consider the following: (a) A certain rocket carries 60% of its initial mas

madreJ [45]

Answer:

$0.916v_{ex}$

Explanation:

A multistage rock is also known as a step rocket and it is a form of vehicle that can use more than a rocket stage. The rocket stage typically contains propellant as well as its engine. The final speed of the rocket can be estimated using the equation below:

$v = v_{ex} ln(\frac{m_{o}}{0.4m_{o}})$ $= v_{ex}*ln(2.5) = v_{ex}*0.916 = 0.916v_{ex}$

Therefore, the maximum speed of the rocket is $0.916v_{ex}$

8 0

4 years ago

A body travels the first half of the total distance with velocity v and second half with v2 calculate avg velocity

LuckyWell [14K]

Answer:

v = 2 v₁ v₂ / (v₁ + v₂)

Explanation:

The body travels the first half of the distance with velocity v₁. The time it takes is:

t₁ = (d/2) / v₁

t₁ = d / (2v₁)

Similarly, the body travels the second half with velocity v₂, so the time is:

t₂ = (d/2) / v₂

t₂ = d / (2v₂)

The average velocity is the total displacement over total time:

v = d / t

v = d / (t₁ + t₂)

v = d / (d / (2v₁) + d / (2v₂))

v = d / (d/2 (1/v₁ + 1/v₂))

v = 2 / (1/v₁ + 1/v₂)

v = 2 / ((v₁ + v₂) / (v₁ v₂))

v = 2 v₁ v₂ / (v₁ + v₂)

8 0

3 years ago

Two electric charges are moved so that they are twice as far apart as they had originally been. Is the force they experience fro

Natasha_Volkova [10]

Answer:

No.

Explanation:

The force that two particle experience is inversely proportional to the sqare of the distance, this is:

$F \ \alpha \ \frac{1}{D^{2}}$ for a distance D

If we move them so that D is doubled:

$\frac{1}{2^{2}.D^{2} }$ = $\frac{1}{4} \eq \frac{1}{.D^{2} } \eq$

Then the force they experience is one fourth of the original.

5 0

3 years ago