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Licemer1 [7]
3 years ago
5

The defense is the team that is trying to score a goal. A. True B. False

Physics
2 answers:
Stolb23 [73]3 years ago
7 0
The defense is the team that is trying to score a goal. False
larisa86 [58]3 years ago
5 0

Answer:

true

Explanation:

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An oscillator consists of a block attached to a spring (k = 427 N/m). At some time t, the position (measured from the system's e
White raven [17]

Answer:

a) 4.49Hz

b) 0.536kg

c) 2.57s

Explanation:

This problem can be solved by using the equation for he position and velocity of an object in a mass-string system:

x=Acos(\omega t)\\\\v=-\omega Asin(\omega t)\\\\a=-\omega^2Acos(\omega t)

for some time t you have:

x=0.134m

v=-12.1m/s

a=-107m/s^2

If you divide the first equation and the third equation, you can calculate w:

\frac{x}{a}=\frac{Acos(\omega t)}{-\omega^2 Acos(\omega t)}\\\\\omega=\sqrt{-\frac{a}{x}}=\sqrt{-\frac{-107m/s^2}{0.134m}}=28.25\frac{rad}{s}

with this value you can compute the frequency:

a)

f=\frac{\omega}{2\pi}=\frac{28.25rad/s}{2\pi}=4.49Hz

b)

the mass of the block is given by the formula:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}\\\\m=\frac{k}{4\pi^2f^2}=\frac{427N/m}{(4\pi^2)(4.49Hz)^2}=0.536kg

c) to find the amplitude of the motion you need to know the time t. This can computed by dividing the equation for v with the equation for x and taking the arctan:

\frac{v}{x}=-\omega tan(\omega t)\\\\t=\frac{1}{\omega}arctan(-\frac{v}{x\omega })=\frac{1}{28.25rad/s}arctan(-\frac{-12.1m/s}{(0.134m)(28.25rad/s)})=2.57s

Finally, the amplitude is:

x=Acos(\omega t)\\\\A=\frac{0.134m}{cos(28.25rad/s*2.57s )}=0.45m

5 0
2 years ago
A 0.11 N m torque is applied to a fan that was initially at rest. The fan has moment of inertia of 0.034 kg m2. Determine the ki
Mars2501 [29]

Answer:

2.72*10-3 Joules

Explanation:

From Newton's second law of motion

F=ma

\tau=I*\alpha

given

\tau= 0.11Nm\\\\I=0.034kgm^2\\\\t= 8s\\\\\alpha=?

\alpha =0.11/0.034\\\\\alpha=3.23 rad/s^2

the angular velocity is

\omega = \alpha/t\\\\\omega =3.23/8\\\\\omega =0.4 rad/s

KE= 1/2*I* \omega^2

KE=1/2*0.034*0.4^2\\\\KE=1/2*0.034*0.16\\\\KE=0.00272\\\\KE=2.72*10^-3J

4 0
2 years ago
Our galaxy, the ______________, contains more than 200 billion stars.
erica [24]

Answer: Milky Way

Explanation:

4 0
3 years ago
Henry was given this cool toy for his birthday, he can use it to tell how fast someone is moving at that moment in time. The toy
Jobisdone [24]
Speed, the toy can calculate a persons speed
6 0
3 years ago
On his fishing trip Justin takes the boat 25 km south. The fish aren’t biting so he goes 10 km west. He follows a school of fish
S_A_V [24]

Distance is 50 km

Displacement is 10 km

<u>Explanation:</u>

Given:

Distance toward south, x = 25 km

Distance towards west, y = 10 km

Distance towards north, z = 15 km

(a) Total distance, D = ?

Total distance, D = x + y + z

                       D = 25 + 10 + 15

                       D = 50km

(b) Displacement, d = ?

Displacement = final position - initial position

                      = 10 - 0 km

                      = 10km

8 0
2 years ago
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