Answer:
a sea breeze is a blowing breeze from sea towards land during the day
Answer:
Explanation:
Relation between Celsius and Kelvin is
K = C + 273
Relation between Kelvin and Fahrenheit is
![\frac{K-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7BK-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
(a) 379 K
Relation between Celsius and Kelvin is
K = C + 273
So, C = K - 273 = 379 - 273 = 106
Thus, 379 K = 106°C.
(b) 379 K
Relation between Kelvin and Fahrenheit is
![\frac{K-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7BK-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
![\frac{379-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7B379-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
F = 222.8°F
Thus, 379 K = 222.8°F
(c) 1.04 x 10^2 K = 104 K
Relation between Celsius and Kelvin is
K = C + 273
So, C = K - 273 = 104 - 273 = -169
Thus, 104 K = - 169°C.
(d) 1.04 x 10^2 K = 104 K
Relation between Kelvin and Fahrenheit is
![\frac{K-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7BK-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
![\frac{104-273}{100}=\frac{F -32}{180}](https://tex.z-dn.net/?f=%5Cfrac%7B104-273%7D%7B100%7D%3D%5Cfrac%7BF%20-32%7D%7B180%7D)
F =- 272.2°F
Thus, 104 K = - 272.2°F
Explanation:
Center of gravity , Let center of rod is origin
= ![\frac{(0.400*0)+(0.800*\frac{50}{2}+10)+ (0.200 *(-(25+5)) }{0.400+0.800+0.200}](https://tex.z-dn.net/?f=%5Cfrac%7B%280.400%2A0%29%2B%280.800%2A%5Cfrac%7B50%7D%7B2%7D%2B10%29%2B%20%280.200%20%2A%28-%2825%2B5%29%29%20%7D%7B0.400%2B0.800%2B0.200%7D)
=15.71cm from the center of rod
Well it determines on how much magnetism a material has.