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irakobra [83]
3 years ago
7

A crossbow:

Physics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

The answer is B.

Explanation:

A crossbow is a type of elastic ranged weapon in similar principle to a bow, consisting of a bow-like assembly called a prod, mounted horizontally on a main frame called a tiller, which is handheld in a similar fashion to the stock of a long gun. It shoots arrow-like projectiles called bolts or quarrels.

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If heat Q is required to increase the temperature of a metal object from 4 ∘C to 7∘C, the amount of heat necessary to increase i
alisha [4.7K]

Answer:

4Q

Explanation:

Case 1 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 7 - 4 = 3 C

Amount of heat required for the above change of temperature is given as

Q = m c \Delta T\\Q = m c (7 - 4)\\Q = 3 m c

Case 2 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 19 - 7 = 12 C

Amount of heat required for the above change of temperature is given as

Q' = m c \Delta T\\Q' = m c (12)\\Q' = (4)(3 m c)\\Q' = 4Q

Hence the correct choice is

4Q

6 0
3 years ago
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The reason a person finds it easier to float in salt water compared with fresh water is that in salt water...
Greeley [361]

Answer:salt pushes up the boat or the vessle of carriage

Explanation:

8 0
3 years ago
By Faraday’s Law, if a conducting wire of length ℓ meters moves at velocity v m/s perpendicular to a magnetic field of strength
sasho [114]

Answer

given,

conducting wire  length =  ℓ m = 0.5

moves at velocity =  v m/s = v ( t ) = 4 t + 9

magnetic field strength = B  = 2 T

V = − B ℓ v

V = - 2 × 0.5 × v

V = - v

a) \dfrac{dV}{dv} = \dfrac{d(-v)}{dv}

   \dfrac{dV}{dv} = -1

b) given

    v ( t ) = 4 t + 9

    V = (-1)(4t + 9)

   \dfrac{dV}{dt} = \dfrac{d((-1)(4t + 9))}{dt}

   \dfrac{dV}{dv} = -4

3 0
3 years ago
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Vesna [10]

Answer:something empty depressed

Explanation:

8 0
1 year ago
The carnival ride has a 2.0m radius and rotates 1.1 times persecond.
Lady_Fox [76]

Answer:

a) v = 13.8 m / s , b) a = 95.49 m / s² , c) a force that goes to the center of the carnival ride  and d)   μ = 0.10

Explanation:

For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics

a) reduce the magnitudes to the SI system

     w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s

The equation that relates linear and angular velocity is

     v = w r

     v = 6.91  2

     v = 13.8 m / s

b) centripetal acceleration is given by

     a = v² / r = w² r

     a = 6.91² 2

     a = 95.49 m / s²

c) this acceleration is produced by a force that goes to the center of the carnival ride

d) Here we use Newton's second law

     fr -W = 0

     fr = W

     μ N = mg

Radial shaft

      N = m a

      N = m w² r

      μ m w²  r = m g

      μ = g / w² r

      μ = 9.8 / 6.91² 2

      μ = 0.10

3 0
3 years ago
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