137,638+52,091 round

Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp

yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

$H_0: \mu=2\\\\H_a:\mu< 2$

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803$

The degrees of freedom for this sample size are:

$df=n-1=52-1=51$

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0

3 years ago

Four times the sum of twice a number and -3 is less than times that same number

MakcuM [25]

Four times the sun of twice a number and -3

3 0

2 years ago

Let T: Mmxn(R)Mmxn(R) be the function defined

alexandr402 [8]

Answer:

True. See the explanation and proof below.

Step-by-step explanation:

For this case we need to remeber the definition of linear transformation.

Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:

1) T(x+y) = T(x) + T(y)

2) T(cv) = cT(v)

For all vectors $x,y \in V$ and for all scalars $c \in R$ . And A is called the domain and B the codomain of T.

Proof

For this case the tranformation proposed is t: $M_{mxn} (R) > M_{nxm} (R)$

Where $T(A) = A^T$

For this case we have the following assumption:

1) The transpose of an nxm matrix is an nxm matrix

And the following conditions:

2) $T(A+B) = (A+B)^T = A^T + B^T = T(A) + T(B)$

And we can express like this $T(A+B) =T(A) + T(B)$

3) If $A \in M_{mxn}(R)$ and $c \in R$ then we have this:

$T(cA) = (cA)^T = cA^T = cT(A)$

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.

5 0

3 years ago

What is the least common multipul of 6 and 8?

Bogdan [553]

Answer:

Step-by-step explanation:

24

The LCM of 6 and 8 is 24. To find the least common multiple (LCM) of 6 and 8, we need to find the multiples of 6 and 8 (multiples of 6 = 6, 12, 18, 24; multiples of 8 = 8, 16, 24, 32) and choose the smallest multiple that is exactly divisible by 6 and 8, i.e., 24.

5 0

3 years ago

Which of the following Could be used to determine the volume of a sheet of metal 50×34 that had identical squares cut out of the

valentinak56 [21]

Answer:

idk

Step-by-step explanation:

8 0

3 years ago