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GrogVix [38]
2 years ago
12

Which of the following types of valves have a valve stem that moves up and down in a valve guide? Select one: a. Poppet valves b

. Reed valves c. Check valves d. All of the above.
Engineering
2 answers:
Alja [10]2 years ago
5 0

Answer:c

Explanation:

thats wht it is

puteri [66]2 years ago
4 0

Poppet valves are the one whose valve stem moves up and down in a valve guide.

Answer: A

Explanation

Poppet valve is used for controlling the flow of fluid in the engine.

The valves are present inside a cylindrical structure from where the fluids will get inserted or exhausted.

The timing of input and output as well the quantity of input and output is maintained by Poppet valve.

The valve consists of a large metal plate connected with a long metal rod.

The metal rod is termed as valve stem which is present in the valve guide.

The valve stem will be moving up and down to insert and exhaust the gases respectively in an internal combustion engine.

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Answer:

Glazier

Explanation:

Glaziers are workers who specializes in cutting and installation of glass works.

They work with glass in various surfaces and settings, such as cutting and installing windows and doors, skylights, storefronts, display cases, mirrors, facades, interior walls, etc.

Thus, the type of worker the contractor will hire for this project is a Glazier

8 0
3 years ago
Which of the following explains the main reason to cut a piece of wood on the outside of the measurement mark?
maks197457 [2]
I think it’s D ?? I’m not completely sure tho
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3 years ago
At the instant under consideration, the hydraulic cylinder AB has a length L = 0.75 m, and this length is momentarily increasing
Inessa [10]

Answer:

vB = - 0.176 m/s   (↓-)

Explanation:

Given

(AB) = 0.75 m

(AB)' = 0.2 m/s

vA = 0.6 m/s

θ = 35°

vB = ?

We use the formulas

Sin θ = Sin 35° = (OA)/(AB) ⇒  (OA) = Sin 35°*(AB)

⇒   (OA) = Sin 35°*(0.75 m) = 0.43 m

Cos θ = Cos 35° = (OB)/(AB) ⇒  (OB) = Cos 35°*(AB)

⇒   (OB) = Cos 35°*(0.75 m) = 0.614 m

We apply Pythagoras' theorem as follows

(AB)² = (OA)² + (OB)²

We derive the equation

2*(AB)*(AB)' = 2*(OA)*vA + 2*(OB)*vB

⇒  (AB)*(AB)' = (OA)*vA + (OB)*vB

⇒  vB = ((AB)*(AB)' - (OA)*vA) / (OB)

then we have

⇒  vB = ((0.75 m)*(0.2 m/s) - (0.43 m)*(0.6 m/s) / (0.614 m)

⇒  vB = - 0.176 m/s   (↓-)

The pic can show the question.

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