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deff fn [24]
3 years ago
13

Saturated liquid-vapor mixture of water, called wet steam, in a steam line at 1500 kPa is throttled to 50 kPa and 100°C. What is

the quality in the steam line?
Engineering
1 answer:
frozen [14]3 years ago
6 0

Answer:

x = 0.944

Explanation:

Steam at outlet is an superheated steam, since T > T_{sat}. From steam tables, the specific enthalpy is:

h_{out}=2682.4\,\frac{kJ}{kg}

The throttle valve is modelled after the First Law of Thermodynamics:

h_{in} = h_{out}

Hence, specific enthalpy at inlet is:

h_{in}=2682.4\,\frac{kJ}{kg}

The quality in the steam line is:

x = \frac{2682.4\,\frac{kJ}{kg}-844.55\,\frac{kJ}{kg}}{2791.0\,\frac{kJ}{kg} - 844.55\,\frac{kJ}{kg} }

x = 0.944

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Complex power for first load:

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Since the power angle of first load is  θ₁ = 0°

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    = 8<53.13° - 3

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    = 138.564

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impedance per phase of the second load:

Z_{p} =  3 V_{p}² / S₂

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   = 57596.6208 / 6.65<74.29°

Z_{p} = 2.35 + j8.34Ω

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