Answer:
shear strength = 2682.31 Ib/ft^2
Explanation:
major principal stress = 100 Ib / in2
minor principal stress = 20 Ib/in2
Normal stress = 3000 Ib/ft2
<u>Determine the shear strength when direct shear test is performed </u>
To resolve this we will apply the coulomb failure criteria relationship between major and minor principal stress a
for direct shear test
use Mohr Coulomb criteria relation between normal stress and shear stress
Shear strength when normal strength is 3000 Ib/ft = 2682.31 Ib/ft^2
attached below is the detailed solution
Answer:
4.5 m/s = 16.2 km/h
Explanation:
The speed is the ratio of distance to time:
speed = (180 m)/(40 s) = 4.5 m/s
Answer:
B a lever because it can move up and down
Explanation:
Hello there,
In the problems given in the question, the driver's license is confiscated and suspended.
So our answer is: A)
Achievements.
Answer:
Explanation:
The concept of Hooke's law was applied as it relates to deformation.
The detailed steps and appropriate substitution is as shown in the attached file.