Answer:
Explanation:
Broaching:
Broaching is a metal removal process or we can say that it is a machining process.Generally broach have three types teeth in which first one is called roughing teeth,second one semi finishing and third one finishing teeth.By using these teeth metal remove so fast and that is why broaching is the high metal removal rate operation.
Answer:
Applied Stress > 58.29 MPa
Explanation:
- Resolved shear stress should be greater than critically resolved shear stress in order to cause the single crystal to yield
Given angles are
∅ = 42.7 degree
Ф = 48.3 degree
Critically resolved shear stress = 28.5 MPa
If we consider
Critically resolved shear stress = resolved shear stress
Applied stress can be found by
(1)
Applied Stress = 
Applied Stress = 
Applied Stress = 58.29 MPa
We got reference
- By putting applied stress values of greater than 58.29 MPa in equation 1 we get
Resolved Shear Stress = 60 x Cos(48.3) x Cos(42.7)
Resolved Shear Stress = 29.33 MPa
Therefore, by the above calculation we conclude that applied stress should be greater than 58.29 MPa, In order to make resolved shear stress to be greater than critically resolved shear stress that is essential for single crystal to yield.
Answer:
the density of the electrum is 14.30 g/cm³
Explanation:
Given that:
The equilibrium fraction of lattice sites that are vacant in electrum = 
Number of vacant atoms = 
the atomic mass of the electrum = 146.08 g/mol
Avogadro's number = 
The Number of vacant atoms = Fraction of lattice sites × Total number of sites(N)
=
× Total number of sites(N)
Total number of sites (N) = 
Total number of sites (N) = 
From the expression of the total number of sites; we can determine the density of the electrum;

where ;
= Avogadro's Number
density of the electrum
= Atomic mass





Thus; the density of the electrum is 14.30 g/cm³
Answer:
Z= 0.868
Explanation:
Given that
P= 3 MPa
T = 160 K
We know that
P v= Z R T
P= Pressure
v = specific volume
R= gas constant
T = Absolute temperature
Z= Compressibility factor
Here specific volume of gas is not given so we assume that specific volume gas

We know that for oxygen gas constant
R = 0.259 KJ/kg.K
Now by putting the values
P v = Z R T
3000 x 0.012 = Z x 0.259 x 160
Z= 0.868
So Compressibility factor is 0.868.
Answer:
a
Explanation:
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