Took a a test and got it correct .... ——-The solubility curve for a gas would start higher and curve downwards as temperature increased
The ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.
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Induced emf</h3>
An emf is induced in a coil placed in a magnetic field when a current carrying conductor moves in the field.
emf = NdФ/dt
where;
- dФ is change in flux of the field
- N is number of turns
- dt is change in time
Thus, the ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.
Learn more about induced emf here: brainly.com/question/13744192
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Answer:
The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x 
N/C
Explanation:
given information,
kinetic energy, KE = 3.25 x 
J
proton's mass, m = 1.673 x 
kg
charge, q = 1.602 x 
C
distance, d = 2 m
to find the electric field that will stop the proton, we can use the following equation:
E = F/q
= (KE/d) / q , KE = Fd --> F = KE/d
= KE/qd
= (3.25 x J) / (1.602 x C)(2 m)
= 1.01 x N/C
Vector trigonometry can be used for this problem. Since the horizontal component is 12 meters per second, this is technically the hypotenuse (actual initial velocity) multiplied to cosine of 40 degrees. Therefore, to find the hypotenuse, we must divide 12 by cosine 40degrees. cos(40)= 0.766, and 12/0.766 = approximately 15.664, therefore our answer is (3) 15.7 m/s
