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3 years ago

Specific heat depends on several factors. Pick the factor below that you suspect will not affect specific heat. composition

Physics

1 answer:

kicyunya [14]3 years ago

6 0

Answer:

COMPOSITION

Explanation:

the correct answer is COMPOSITION.

specific heat of the body can be defined as the heat required to raise the temperature of a unit mass of a body by 1 °C.

so, A composition of the material is not affected by the specific heat.

The unit of specific heat is Joule per kelvin (J / K ).

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A convex mirror curves ___________.<br><br> what does a convex mirror curves?

Lesechka [4]

So, a concave mirror is a mirror that goes inward, thus, making a convex mirror have an outward curvature. Ex: A convex mirror is used at the front of a bus.

6 0

3 years ago

Read 2 more answers

Arightward force of 302 N is applied to a 28.6-kg crate to accelerate it across the floor. What will its acceleration be?

Musya8 [376]

Answer:

a $\approx$ 10.6 m/s²

Explanation:

Since F = ma (Force = mass * acceleration), acceleration would be...

a = F/m

a = 302 N/28.6

a $\approx$ 10.6 m/s²

8 0

3 years ago

Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out

PolarNik [594]

Answer:

The two value of the wavelength for the out of tune guitar is

$\lambda _2 = (6.48,6.52) \ cm$

Explanation:

From the question we are told that

The wavelength of the note is $\lambda = 6.50 \ cm = 0.065 \ m$

The difference in beat frequency is $\Delta f = 17.0 \ Hz$

Generally the frequency of the note played by the guitar that is in tune is

$f_1 = \frac{v_s}{\lambda}$

Where $v_s$ is the speed of sound with a constant value $v_s = 343 \ m/s$

$f_1 = \frac{343}{0.0065}$

$f_1 = 5276.9 \ Hz$

The difference in beat is mathematically represented as

$\Delta f = |f_1 - f_2|$

Where $f_2$ is the frequency of the sound from the out of tune guitar

$f_2 =f_1 \pm \Delta f$

substituting values

$f_2 =f_1 + \Delta f$

$f_2 = 5276.9 + 17.0$

$f_2 = 5293.9 \ Hz$

The wavelength for this frequency is

$\lambda_2 = \frac{343 }{5293.9}$

$\lambda_2 = 0.0648 \ m$

$\lambda_2 = 6.48 \ cm$

For the second value of the second frequency

$f_2 = f_1 - \Delta f$

$f_2 = 5276.9 -17$

$f_2 = 5259.9 Hz$

The wavelength for this frequency is

$\lambda _2 = \frac{343}{5259.9}$

$\lambda _2 = 0.0652 \ m$

$\lambda _2 = 6.52 \ cm$

8 0

3 years ago

One type of ride falls straight down for 3 seconds. During this time, the ride accelerates from a speed of 0 m/s to a speed of 3

Alja [10]

Answer:

Initial speed: 0m/s Final speed: 30m/s Time: 3 seconds Average Acceleration: 10m/s

Explanation:

I'm not sure if this is right... but you take the final speed and divide it by the time... just dont take advice from me anymore i guess

7 0

3 years ago

A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. What is the acceleration experie

Harman [31]

Answer:

Explanation:

Given that, the pilot can withstand 9g acceleration which is approximately 88m/s².

Now, the pilot is traveling in a circle of radius

r = 3340 m

And the speed is

v = 495 m/s

Then, acceleration?

The acceleration of a circular motion can be determine using centripetal acceleration

a = v² / r

a = 495² / 3340

a = 73.36 m/s².

Since the acceleration is less that the acceleration the pilot can withstand, then, I think the pilot makes the turn without blacking out and successfully

4 0

4 years ago