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Kamila [148]
3 years ago
12

5. An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and

the two objects stick together. If the momentum is conserved, what is the new velocity of the combined object? Round to the nearest hundredth.
A. 34.78 m/s
B. 15.82 m/s
C. 69.56 m/s
D. 18.60 m/s​
Physics
1 answer:
marishachu [46]3 years ago
4 0

Answer:

D. 18.60

Explanation:

By the law of conservation, the momentum is neither loss nor gained but instead transfered. When they crash into each other, and stick, they combine to create a total mass of 215 kg. Since the momentum is transfered, the two objects, combined, have a total momentum of 4000 kg-m/s. We know that momentum equals mass times velocity. You then divide 4000 by 215 and get approximately 18.6 m/s

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The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What
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The formula we need to use is displacement.

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2 years ago
Supposing d(t) is known to have value D,
creativ13 [48]

Answer:

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Explanation:

This question assumes uniformly accelerated motion, for which the distance d a particle travels in time t is given by the general equation:

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That is a quadratic equation, where the independent variable is the time t.

Thus, the procedure that will find the time t at which the distance value is known to be D is to solve the quadratic equation for t.

To solve it you start by changing the equation to the general form of the quadratic equations, rearranging the terms:

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Some times that equation may be solved by factoring, and always it can be solved by using the quadratic formula:

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Where:

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That may have two solutions. Some times one of the solution makes no physical sense (for example time cannot be negative) but others the two solutions are valid.

5 0
3 years ago
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I had a question like this one time and the answer is a pound of cement
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3 years ago
Read 2 more answers
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