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scZoUnD [109]
3 years ago
13

HELP ME !!!Question 4 of 10

Physics
2 answers:
Dmitrij [34]3 years ago
8 0

Answer:

The answers are C and D

Explanation:

Apex

kobusy [5.1K]3 years ago
8 0

Answer:

C: From the pot to the water

D: From the burner to the bottom of the pot

Explanation:

--APEX-- HOPE THIS HELPS!!

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Parallax error occurs when the observer records data when he/she is at an angle to the event he/she is observing. Where do you t
kompoz [17]

Answer:Orient your line of sight directly above the measurement markings.

Explanation: parallax error is a type of systematic error that occurs when an observer views a measurement marking at a wrong angle. This causes a noticeable disparity in results obtained. Therefore the best way to prevent this error is to view and record the data from the correct angle. This can be obtained by:

-Place the measurement device on its edge so it is level with the object being measured.

-Seek out the finest possible edge of the measurement device, or use a device with finer edges.

In conclusion, ask other observers to also take the reading and get an average of their results. It can help cancel out parallax error results.

4 0
3 years ago
Which of the following is an example of an acceptable time to ignore the rules and etiquette of a sport?
Helga [31]

Answer:

D-it's never acceptable to ignore rules and etiquette

Explanation:

4 0
2 years ago
Read 2 more answers
A 2kg mass is moving at 3m/s. What is its kinetic energy?
Illusion [34]
<h2><u>KINETIC ENERGY</u></h2>

<h3>Problem:</h3>

» A 2kg mass is moving at 3m/s. What is its kinetic energy?

<h3>Answer:</h3>
  • \color{hotpink} \bold{9 \: J} \\

— — — — — — — — — —

<h3>Formula:</h3>

To calculate the velocity of a kinetic energy, we can use formula

  • \underline{ \boxed{  \tt KE =  \frac{1}{2} m{v}^{2}  } }

where,

  • v is the velocity in m/s
  • KE is the kinetic energy in J (joules)
  • m is the mass in kg

— — —

Based on the problem, the givens are:

  • KE (Kinetic energy) = ? (unknown)
  • m (mass) = 2 kg
  • v (velocity) = 3 m/s

<h3>Solution:</h3>

To get the velocity, substitute the givens in the formula above then solve.

\:   \: \tt KE =  \frac{1}{2} m{v}^{2}   \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \tt \:   KE =  \frac{1}{2} \times  2 \times {(3)}^{2}  \\ \tt  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  KE =  \frac{1}{2}  \times(2\times 9) \\ \tt  KE =  \underline{ \boxed{ \blue{ \tt9 \: J}}}

Therefore, the kinetic energy is 9 Joules.

3 0
1 year ago
Please help for 21! will mark brainliest
Katyanochek1 [597]

The answer for this question is D

5 0
2 years ago
Two tiny particles having charges 20.0 μC and 8.00 μC are separated by a distance of 20.0 cm What are the magnitude and directio
Alecsey [184]

Answer:

The magnitude and direction of electric field midway between these two charges is 10.8\times10^{5}\ N/C along AB.

Explanation:

Given that,

First charge q_{1}= 20\mu C

second charge q_{2}= 8\mu C

Distance = 20 cm

We need to calculate the electric field

For first charge,

Using formula of electric field

E_{1}= \dfrac{kq_{1}}{r^2}

Put the valueinto the formula

E_{1}=\dfrac{9\times10^{9}\times20\times10^{-6}}{10\times10^{-2}}

E_{1}=18\times10^{5}\ N/C

Direction of electric field along AB

We need to calculate the electric field

For second charge,

Using formula of electric field

E_{2}= \dfrac{kq_{2}}{r^2}

Put the valueinto the formula

E_{2}=\dfrac{9\times10^{9}\times8\times10^{-6}}{10\times10^{-2}}

E_{2}=7.2\times10^{5}\ N/C

Direction of electric field along AO

We need to calculate the net electric field at midpoint

E_{net}=E_{1}-E_{2}

E_{net}=(18-7.2)\times10^{5}\ N/C

E_{net}=10.8\times10^{5}\ N/C

Direction of net electric field along AB

Hence, The magnitude and direction of electric field midway between these two charges is 10.8\times10^{5}\ N/C along AB.

8 0
3 years ago
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