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monitta
3 years ago
9

Hi, I am having issues with this physics question. I find it quite complicated to solve and I don't even have the answer to this

question. Could someone please explain me this question and give me the answer? Thanks! ​

Physics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

200 m

Explanation:

Both Jerry and Tom start at the end of the pipe where the cheese is.  Jerry then runs into the pipe at 20 m/s while Tom chases him at 10 m/s.  When Jerry reaches the other end of the pipe, where Tom's cousin is, he turns around.  Eventually, he reaches Tom again, so he turns around again.  This continues until both Tom and Jerry reach the end of the pipe where Tom's cousin is.

We need to find the distance traveled by Jerry.  We already know Jerry's speed, so we just need to find the time.  We can do that using Tom's speed and the length of the pipe.

x = vt

100 m = (10 m/s) t

t = 10 s

So both Tom and Jerry run for 10 seconds.  Since Jerry runs at a speed of 20 m/s, the distance he travels is:

x = vt

x = (20 m/s) (10 s)

x = 200 m

Jerry runs a distance of 200 meters.

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The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the
Ainat [17]
When  t=2, the ball has fallen     d(2) = 16 (2²) = 64 feet .

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6 0
3 years ago
What must be the acceleration of a train in order for it to stop 12 m/s in a distance if 541 m
earnstyle [38]

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

Lets explain how to solve the problem

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

We want to find its acceleration

The acceleration will be negative quantity because the train reduced its

velocity from 12 m/s to zero

We need rule contains velocity, acceleration and distance

So we will use ⇒<em> v² = u² + 2as</em>, where v is the final velocity, u is the

initial velocity, a is the acceleration and s is the distance

v = 0, u = 12 m/s, s = 541 m

Substitute these values in the rule

(0)² = (12)² + 2(a)(541)

0 = 144 + 1082 a

Subtract 144 from both sides

-144 = 1082 a

Divide both sides by 1082

- 0.133 = a

<em>The acceleration of the train must be - 0.133 m/s²</em>

3 0
3 years ago
An air hockey game has a puck of mass 30 grams and a diameter of 100 mm. The air film under the puck is 0.1 mm thick. Calculate
OverLord2011 [107]

Answer:

time required after impact for a puck is 2.18 seconds

Explanation:

given data

mass = 30 g = 0.03 kg

diameter = 100 mm = 0.1 m

thick = 0.1 mm = 1 ×10^{-4} m

dynamic viscosity = 1.75 ×10^{-5} Ns/m²

air temperature = 15°C

to find out

time required after impact for a puck to lose 10%

solution

we know velocity varies here 0 to v

we consider here initial velocity = v

so final velocity = 0.9v

so change in velocity is du = v

and clearance dy = h

and shear stress acting on surface is here express as

= µ \frac{du}{dy}

so

= µ  \frac{v}{h}   ............1

put here value

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and

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and now apply newton second law

force = mass × acceleration

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t =  \frac{0.1 v * 0.03}{1.37*10^{-3} v}

time = 2.18

so time required after impact for a puck is 2.18 seconds

3 0
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