A ball of mass m, attached to the end of a horizontal cord, is rotated in a circle of radius r on a frictionless horizontal surf
1 answer:
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Answer:
speed of a particle = 2.31 × m/s
energy of proton required = 27.77 KeV
energy of electron required = 15.171 eV
Explanation:
given data
magnetic field of magnitude = 0.22 T
electric field of magnitude = 0.51 MV/m
to find out
speed of a particle and energy must protons have to pass through undeflected and energy must electrons have to pass through undeflected
solution
we know that force due to magnetic and electric field is express as
force due to magnetic field B = qvB ..............1
and force due to electric field E = qE .....................2
so without deflection force due to magnetic field = force due to electric field
so here qvB = qE
and V = ...................3
put here value
V =
speed of a particle = 2.31 × m/s
and
now energy of proton required will be here as
energy of proton required = mass of proton ×
put here value
energy of proton required = 1.67 × ×
energy of proton required = 4.45 × J
energy of proton required = 4.45 × J ÷ (1.602 ×
energy of proton required = 27777.777 eV
energy of proton required = 27.77 KeV
and
now we get here energy of electron required that is
energy of electron required = mass of electron ×
put here value
energy of electron required = 9.11 × ×
energy of electron required = 24.305× J
energy of electron required = 24.305 × J ÷ (1.602 ×
energy of electron required = 15.171 eV
Answer:
It will take 4 sec rock to comes its original point
Explanation:
It is given that the rock comes to its original point
So displacement S = 0 m
Initial velocity u = 19.6 m/sec
Acceleration due to gravity
According to second equation of motion
t = 4 sec