Answer:
A) 48 in : initial height of the water
B) 40.5 in : height of the water after 5 days
C) 32 days
D) Yes, should be restricted.
Domain: 0 ≤ d ≤ 32
Step-by-step explanation:
A)
48 in is the initial height of the water
B)
40.5 in is the height of the water after 5 days
C) when the pool is empty, h = 0.
So set the equation to zero and solve for d.
D) Yes, the domain should be restricted because when d > 32, h < 0 and the height of the water in the pool cannot be negative
Domain: 0 ≤ d ≤ 32
Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
In a normal distribution with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of
.
- The standard deviation is of
.
- Sample of 100, hence
The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:
Z = -2:
By the Central Limit Theorem
Z = 2:
The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
To simplify fractions, all you have to do is divide both the numerator and the denominator by the greatest common factor of both integers.
In this case, the greatest common factor of 2 and 10 is 2.
2/2=1
10/2=5
So, 2/10 in its simplest form is 1/5.
Answer: The limit does not exist.
Please, see the attached file.
Thanks.
Answer and Step-by-step explanation:
For these system of equations, it would be easier to use the substitution method, as we are have one equation that is being equaled to a variable.
Plug the second equation into the value of b for the first equation.
5a + 3(-2a + 3) = 11
Distribute the 3.
5a - 6a + 3 = 11
Simplify.
-a + 3 = 11
Subtract 3 from both sides of the equation.
-a = 8
Divide both sides by -1.
a = -8
Now, we can plug this value into the second equation.
-2(-8) + 3 = b
Multiply -2 and -8 together.
16 + 3 = b
Add together 16 and 3.
19 = b
<u>a = -8</u>
<u>b = 19</u>
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<em><u>#teamtrees #PAW (Plant And Water)</u></em>
