Answer:
A.) 8 m/s
B.) 7.0 m
Explanation:
Given that a block is given an initial velocity of 8.0 m/s up a frictionless 28° inclined plane.
(a) What is its velocity when it reaches the top of the plane?
Since the plane is frictionless, the final velocity V will be the same as 8 m/s
The velocity will be 8 m/s as it reaches the top of the plane.
(b) How far horizontally does it land after it leaves the plane?
For frictionless plane,
a = gsinø
Acceleration a = 9.8sin28
Acceleration a = 4.6 m/s^2
Using the third equation of motion
V^2 = U^2 - 2as
Substitute the a and the U into the equation. Where V = 0
0 = 8^2 - 2 × 4.6 × S
9.2S = 64
S = 64/9.2
S = 6.956 m
S = 7.0 m
Answer:
40 meters. look for the dot above the 20 on the x-axis and follow it over to the left.
Explanation:
I think you always draw the gravity component. I'm not exactly sure though.
The magnitude of the magnetic field inside the solenoid is 4.56 X 10-3 T
A magnetic subject is a vector subject that describes the magnetic effect on shifting electric fees, electric currents, and magnetic materials. A shifting rate in a magnetic subject experiences a force perpendicular to its own speed and to the magnetic area.
A magnetic area is a vector area that describes the magnetic have an impact on transferring electric powered prices, electric powered currents, and magnetic substances. A moving rate in a magnetic area studies a force perpendicular to its very own pace and to the magnetic subject.
Calculation
B = UNI/L
B = (4pi X 10-7)(25)(1.45)/(.01)
B = 4.56 X 10-3 T
Learn more about magnetic field here - brainly.com/question/26051825
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