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AveGali [126]
2 years ago
5

A 50 kg person receives an absorbed dose of gamma radiation of 20 millirads. What is the total energy absorbed?.

Physics
1 answer:
Masteriza [31]2 years ago
4 0

For a 50 kg person receives an absorbed dose of gamma radiation of 20 millirads,  the total energy absorbed is mathematically given as

E=0.1457J

<h3>What is the total energy absorbed?</h3>

Generally, the equation for the total energy absorbed  is mathematically given as

E=mass*gamma radiation

Therefore

E=50*20*19^{-3}

E=0.1457J

In conclusion,  the total energy absorbed

E=0.1457J

Read more about Energy

brainly.com/question/13439286

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For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0
3 years ago
3
Elanso [62]

Answer:

ive got no idea just ask your teacher

7 0
2 years ago
ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. A person walks along
Elza [17]
To find the total number of miles traveled by a person, we add the distance that he has traveled: 3.0 + 5.00 + 4.000. 

Now, to find the accurate number of significant figures when adding measurements, the basic rule for addition is to use the least number of decimal places when reporting the result.

Now, since 3.0 has the least number of decimal places, we report the sum with 1 decimal place and have 12.0 miles as the total distance traveled by the person to reach his destination.

Answer: 12.0 miles
8 0
3 years ago
Which would require a greater force -accelerating a 10g mass at 5ms-2 or a 20g mass at 2ms-2?
Trava [24]
Force 1 = 10/1000 × 5 = 0.05 N
Force 2 = 20/1000 × 2 = 0.04 N

F1>F2

so the answer is Force 1
5 0
3 years ago
Read 2 more answers
Pause
nirvana33 [79]

Answer:

C

Explanation:

a=f/m

10Kgm/s2/4kg

2.5m/s2

3 0
3 years ago
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