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Rama09 [41]
4 years ago
8

When the Moon is directly between the Sun and Earth, a _____ tide will occur along a shoreline that is facing the Moon.

Physics
1 answer:
Temka [501]4 years ago
8 0
<span>When the Moon is directly between the Sun and Earth, a spring tide will occur along a shoreline that is facing the Moon. </span>
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What is the relationship in which the ratio of the manipulated variable and the responding variable is constant?
son4ous [18]
That's a 'direct' or 'proportional' variation.

The variables are related by the equation      Y = K X .

That constant ratio is the number    ' K ' .

5 0
3 years ago
Late one night on a highway, a car speeds by you and fadesinto the distance. Under these conditions the pupils of your eyes(aver
Andrews [41]

Answer:

10432.19076 m

Explanation:

\lambda = Wavelength = 660 nm

d = Diameter of pupils = 6 mm

s = Distance between lights = 1.4 m

L = Distance from observer

From Rayleigh's criteria we have

1.22\lambda=dsin\theta

As \theta is small sin\theta=\dfrac{s}{L}

So, the equation becomes

1.22\lambda=d\dfrac{s}{L}\\\Rightarrow L=\dfrac{ds}{1.22\lambda}\\\Rightarrow L=\dfrac{6\times 10^{-3}\times 1.4}{1.22\times 660\times 10^{-9}}\\\Rightarrow L=10432.19076\ m

The car is 10432.19076 m from me

6 0
4 years ago
Scientists described light as a wave because the results of many experiments with light demonstrated that light behaves as a wav
seropon [69]
B and C are both correct.
5 0
3 years ago
What potential difference is needed to stop an electron that has an initial velocity v=6.0
Assoli18 [71]

Formula for kinetic energy of an object:

KE = 0.5mv²

m is the mass and v is the velocity.

Formula for the work done on a charged object by moving it through a potential difference:

W = ΔVq

ΔV is the potential difference and q is the charge of the object.

To find the potential difference needed to decelerate an electron to rest, set the work done on the electron equal to its kinetic energy:

W = KE

Substitute W = ΔVq and KE = 0.5mv²

ΔVq = 0.5mv²

Given values:

q = 1.6×10⁻¹⁹C

m = 9.11×10⁻³¹kg

v = 6.0m/s

Plug in the given values and solve for ΔV

ΔV×1.6×10⁻¹⁹ = 0.5×9.11×10⁻³¹×6.0²

ΔV = 1.02×10⁻¹⁰V

7 0
3 years ago
If you traveled 50m/s for 60 seconds, how far did you travel? Remember speed=distance/time
dlinn [17]

Answer:

3,000 m

Explanation:

speed = distance/time

distance = speed * time

= 50 * 60

= 3000 m

4 0
3 years ago
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