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astra-53 [7]
4 years ago
11

If a charged particle is moving parallel to a magnetic field, it experiences

Physics
1 answer:
aleksandr82 [10.1K]4 years ago
3 0

Answer:it experiences no force

Explanation:

a charge moving in a direction parallel to the magnetic field experience no force.since the angle e is 0,force would also be 0

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A proton of mass is released from rest just above the lower plate and reaches the top plate with speed . An electron of mass is
xenn [34]

Answer:

  v = √ 2e (V₂-V₁) / m

Explanation:

For this exercise we can use the conservation of the energy of the electron

At the highest point. Resting on the top plate

         Em₀ = U = -e V₁

At the lowest point. Just before touching the bottom plate

        Emf = K + U = ½ m v² - e V₂

Energy is conserved

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          -eV₁ = ½ m v² - e V₂

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Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle
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Answer : The de-Broglie wavelength of this electron, 0.101\AA

Explanation :

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According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{mv}

or,

v=\frac{h}{m\lambda}      ...........(2)

Now put the equation (2) in equation (1), we get:

\lambda=\frac{h}{\sqrt{2\times m\times K.E}}  ...........(3)

where,

\lambda = wavelength = ?

h = Planck's constant = 6.626\times 10^{-34}Js

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Now put all the given values in the above formula (3), we get:

\lambda=\frac{6.626\times 10^{-34}Js}{\sqrt{2\times 9.11\times 10^{-31}Kg\times 4.71\times 10^{-15}J}}

\lambda=1.0115\times 10^{-11}m=0.101\AA

conversion used : (1\AA=10^{-10}m)

Therefore, the de-Broglie wavelength of this electron, 0.101\AA

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Explanation:

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