Answer:
b.
Explanation: I do not know much about this but the answer that i think it is was b.
Answer:
pull
is your answer please give me some thanks
Answer:
v = 54 m/s
Explanation:
Given,
The maximum height of the flight of golf ball, h = 150 m
The velocity at height h, u = 0
The velocity of the golf ball right before it hits the ground, v = ?
Using the III equations of motion
<em> v² = u² + 2gh</em>
Substituting the given values in the above equation,
v² = 0 + 2 x 9.8 x 150 m
= 2940
v = 54 m/s
Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s
Answer:
5.9 x 10⁻⁷m
Explanation:
Given parameters:
Frequency = 5.085 x 10¹⁴Hz
Speed of light = 3.0 x 10⁸m/s
Unknown:
Wavelength of the orange light = ?
Solution:
The wavelength can be derived using the expression below;
wavelength = 
v is the speed of light
f is the frequency
wavelength = 
= 5.9 x 10⁻⁷m
Answer:
d / λ = 26.7
Explanation:
In Young's double slit experiment, constructive interference is described by the expression
d sin θ = m λ
In the case of destructive interference we must add half wavelength (λ/2)
d siyn θ = (m + ½) λ
Let's clear
d / λ = (m + ½) / sin θ
Let's calculate
d / λ = (2+ ½) / sin 5.4
d / λ = 5 / (2 sin 5.4)
d / λ = 26.7
