The concept required to solve this problem is linked to inductance. This can be defined as the product between the permeability in free space by the number of turns squared by the area over the length. Recall that Inductance is defined as the opposition of a conductive element to changes in the current flowing through it. Mathematically it can be described as

Here,
= Permeability at free space
N = Number of loops
A = Cross-sectional Area
l = Length
Replacing with our values we have,



Therefore the Inductance is 
Im not so sure but it should be the
instantaneous speed
Answer:
Displacement from the starting position is 103.21m
Explanation:
If you draw these directions, it will create the two legs of a triangle.
Using this method, you can visualize why your displacement is what it is.
Using the pythagorean theorem

Plug in both values


c = 103.2085
c= 103.21
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