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3 years ago

A 5 kg block is pulled with a force of 11 n and accelerates 2 m/s. What is the kinetic friction

Physics

1 answer:

Alexus [3.1K]3 years ago

3 0

Answer:

The coefficient of kinetic friction is .0204081633 and the firction acting upon the object is 1 N

Explanation:

To figure this out I started off with Newton's Second Law F= ma.

(11-x)=5*2. *x is the amount of force that kinetic friction applies on the object

x=1 N

Since F=1 and Friction=Normal-Force*Coifficient-Of-Friction

1=5g(mu)

mu=.0204081633

Hope this helps

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An electromagnetic wave has a frequency of 1.0 x 10^5. What is the wavelength of the wave?

SashulF [63]

Answer:

The frequency , speed and wavelength of an electromagnetic wave are related by the formula

Speed = frequency x wavelength

frequency = speed / wavelength

substituting the values

frequency = 3 x #10 ^8# m /s / 1 x #10^15# m

= 3 x #10^-7# /s

6 0

3 years ago

Read 2 more answers

The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a

s344n2d4d5 [400]

Answer:

82780.42123 m/s

14.45 days

Explanation:

m = Mass of the planet

M = Mass of the star = $0.85\times 1.989\times 10^{30}\ kg=1.69065\times 10^{30}\ kg$

r = Radius of orbit of planet = $0.11\times 149.6\times 10^{9}\ m=16.456\times 10^{9}\ m$

v = Orbital speed

The kinetic and potential energy balance is given by

$\frac{GMm}{r^2}=\frac{mv^2}{r}\\\Rightarrow v=\sqrt{\dfrac{Gm}{r}}\\\Rightarrow v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.69065\times 10^{30}}{16.456\times 10^{9}}}\\\Rightarrow v=82780.42123\ m/s$

The orbital speed of the star is 82780.42123 m/s

The orbital period is given by

$t=\frac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi \times 16.456\times 10^{9}}{82780.42123}\\\Rightarrow t=1249040.48419\ seconds=\dfrac{1249040.48419}{24\times 60\times 60}=14.45\ days$

The orbital period is 14.45 days

5 0

3 years ago

Fuse should not be connected with neutral wire.Why? Write any two electric devices.

Colt1911 [192]

Answer: Because the fuse can disconnect the circuit only when the excess current flows completely through the neutral. ... Since, neutral is not a live conductor coming from the source, disconnecting a neutral line can only open the current path through neutral. But, the live phase still carries the charge.

Explanation:

8 0

3 years ago

The reactants for a certain chemical reaction are shown. Cu(NO3)2 + NaOH → Which of the following shows the correct product or p

valentinak56 [21]

Answer : The products of this reaction are, $Cu(OH)_2$ and $NaNO_3$

Explanation :

First we have to write the balanced chemical reaction.

$Cu(NO_3)_2+2NaOH\rightarrow Cu(OH)_2+2NaNO_3$

In this reaction, 1 mole of copper nitrate react with the 2 moles of sodium hydroxide to give 1 mole of copper hydroxide and 2 moles of sodium nitrate.

This reaction is a double displacement reaction.

Double displacement reaction : A type of reaction in which a positive cation and a negative anion of two reactants react to exchange their places to form two new products.

The general representation of this reaction is,

$XY+AB\rightarrow XB+AY$

(X and A are the cations, Y and B are the anions)

Hence, the products of this reaction are, copper hydroxide, $Cu(OH)_2$ and sodium nitrate, $NaNO_3$

6 0

3 years ago

A 7.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi

Anvisha [2.4K]

Answer:

(a) 1.075 N

(b) 4.254 T

Explanation:

(a)

From the question,

Power = Force×Velocity.

P = Fv................... Equation 1

Where P = Power dissipated in the circuit, F = Pulling force of the wire, v = speed of the wire.

make F the subject of the equation

F = P/v................. Equation 2

Given: P = 4.30 W, v = 4.0 m/s.

Substitute into equation 2

F = 4.30/4

F = 1.075 N.

(b)

Applying,

F = BILsinФ.............. Equation 2

Where B = Strength of the magnetic field, I = current in the wire, L = Length of the wire, Ф = angle between the wire and the magnetic field.

make B the subject of the equation

B = F/ILsinФ................... Equation 3

But,

P = I²R...................... Equation 4

Where R = resistance of the wire.

make I the subject of the equation

I = √(P/R)............... Equation 5

Given: P = 4.30 W, R = 0.330 Ω

Substitute into equation 5

I = √(4.3/0.33)

I = √13.03

I = 3.61 A.

Also given: L = 7 cm = 0.07 m, Ф = 90°

Substitute into equation 3

B = 1.075/(0.07×3.61×sin90)

B = 1.075/0.2527

B = 4.254 T.

4 0

3 years ago