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3 years ago

What is the most striking part of the Rutherford scattering stimulation?

Chemistry

1 answer:

Sati [7]3 years ago

3 0

Answer:

None of the alpha particles fired at the foil are being repelled back, like they were in the Rutherford atom simulation.I hope this is correct.

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La densidad del óxido de magnesio. MgO, es de 3.581 g/cm3 El MgO, es de 3.581 g/cm3 El MgO cristaliza con ordenamiento cúbico co

Jobisdone [24]

Answer:

$a=4.213cm$

$r=1.490x10^{-8}cm$

Explanation:

Hola.

En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:

$\rho =\frac{#at*M}{a^3N_A}$

En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:

$3.581g/mol = \frac{4atom/celda*40.3g/mol}{a^3*6.02x10^{23}atom/mol}$

Despejando para a, obtenemos:

$a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm$

Finalmente, el radio lo calculamos como:

$r=\frac{\sqrt{2}*a}{4}=\frac{\sqrt{2}*4.213x10^{-8}cm}{4}\\\\r=1.490x10^{-8}cm$

¡Saludos!

6 0

3 years ago

How many molecules are in 5.50 grams of AgNO3?

mixas84 [53]

Answer:

1.95*10²² molecules are in 5.50 grams of AgNO₃

Explanation:

Being the molar mass of the elements:

Ag: 107.87 g/mole
N: 14 g/mole
O: 16 g/mole

then the molar mass of the compound is:

AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole

Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?

$moles=\frac{5.50 grams*1 mole}{169.87 grams}$

moles= 0.0324

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?

$molecules=\frac{0.0324 moles*6.023*10^{23} molecules}{1 mole}$

molecules=1.95*10²²

1.95*10²² molecules are in 5.50 grams of AgNO₃

3 0

2 years ago

How many significants are in 54.0047

erik [133]

Answer:

There are 6

Explanation:

The significant figures in that number are 5 4 0 0 4 7

Hope this helps:)

6 0

3 years ago

5. Extend your thinking: What strategies did you use to hunt for moths?

Sonja [21]

Answer: There are many strategies used to hunt and kill moths. I’ll tell you my way of hunting and killing moths.

Step-By-Step Explanation:
Morning and Afternoon: First, get a sticky trap. You can get it at Target or Walmart. Cover it with moth pheromones or anything you know that can attract the moths. The sticky trap, will stick them to the trap and will eventually die after no being able to escape for a long time.
Nighttime: Buy or Get a lamp and turn it on. This will attract lots of moths and it will help you see them. Then, spray insecticide or insect repellent at the. Lastly, they should die.
Tip: If things get too out of hand with a huge swarm of moths, then call pest control and they will surely get rid of them for you!

8 0

2 years ago

Factor f(x)=x² + 4x +3

My name is Ann [436]

Answer:

f(x)=(x+1)(x+3)

Explanation:

7 0

2 years ago