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vladimir1956 [14]
3 years ago
10

5. What would you expect to happen if the cup of olive oil in question 4a is poured into a container of

Chemistry
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

shi i dont know

Explanation:

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Not too sure about this one
Kazeer [188]

Answer:

It should be polarity

8 0
3 years ago
Hi!! please help :( lots of points !
andreev551 [17]

Answer:

<u><em>Structure:</em></u>

<em>Differences-  </em>A polymer is a collection of a large number of molecules whereas a monomer is a single molecule.

A monomer is a single molecule, which has the ability to chemically bond with other monomers in a long chain. A polymer is a chain that is made when monomers bind with other monomers.

<em>Similarities-</em>  They are both molecules

<u><em>Properties:</em></u>

<em> Differences- </em>Monomers have polyfunctionality, which is the capacity to form chemical bonds to at least two other monomer molecules. Polymers are chemically unreactive, solids at room temperature, malleable, tough, and are electrical insulators.

<em>Similarities- </em>They both makeup larger forms of matter.

<u><em>Intermolecular Forces</em></u>

<em>Differences: </em>Polymers are held together by covalent bonds, hydrogen bonds, and dispersion bonds. Monomers are <u><em>only</em></u> held together by hydrogen bonds.

<em>Similarities: </em>They can both be bonded together by hydrogen bonds.

3 0
1 year ago
Under the Doppler Effect, an observer behind a moving wave source observes
disa [49]
Attachment is the answer
3 0
3 years ago
Read 2 more answers
Like all equilibrium constants, the value of Kw depends on temperature. At body temperature (37°C), Kw = 2.4 * 10-14. What are t
Aleksandr [31]

Answer:

pH = 6.8124

Explanation:

We know pH decreases with increase in temperature.

At room temperature i.e. 25⁰c pH of pure water is equal to 7

We know

Kw = [H⁺][OH⁻]...............(1)

where Kw = water dissociation constant

At equilibrium [H⁺] = [OH⁻]

So at 37⁰c i.e body temperature Kw = 2.4 × 10⁻¹⁴

From equation (1)

[H⁺]² = 2.4 × 10⁻¹⁴

[H⁺] = √2.4 × 10⁻¹⁴

[H⁺] = 1.54 × 10⁻⁷

pH  = - log[H⁺]

      = - log{1.54 × 10⁻⁷}

      = 6.812

5 0
3 years ago
A diprotic acid, H₂A, has Ka1 = 3.4 × 10⁻⁴ and Ka2 = 6.7 × 10⁻⁹. What is the pH of a 0.18 M solution of H₂A?
Tcecarenko [31]

Answer:

pH = 2.10

Explanation:

We name an acid as diprotic because it can release two protons:

H₂A  +  H₂O  ⇄  H₃O⁺   + HA⁻     Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺   + A⁻²      Ka₂

We propose the mass balance:

Analytical concentration = [H₂A] +  [HA⁻]  + [A⁻²]

As Ka₂ is so small, we avoid the [A⁻²] so:

0.18 M = [H₂A] +  [HA⁻]

But we can not avoid the HA⁻, because the Ka₁. Ka₁'s expression is:

Ka₁ = [H₃O⁺] . [HA⁻] / [H₂A]

We propose the charge balance:

[H₃O⁺] = [HA⁻] + [A⁻²] + [OH⁻]

As we did not consider the A⁻², we can miss the term and if

Kw = H⁺ . OH⁻

We replace Kw/H⁺ = OH⁻. So the new equation is:

[H₃O⁺] = [HA⁻] + Kw / [H₃O⁺]

The acid is so concentrated, so we can avoid the term with the Kw, so:

[H₃O⁺] = [HA⁻]

In the mass balance we would have:

0.18 M = [H₂A]

We replace at Ka₁

Ka₁ = [H₃O⁺] . [HA⁻] / [H₂A]

Ka1 . 0.18 / [H₃O⁺] = [HA⁻]

We replace at the charge balance:

[H₃O⁺] = Ka1 . 0.18 / [H₃O⁺]

[H₃O⁺]² = 3.4×10⁻⁴  . 0.18

[H₃O⁺] = √(3.4×10⁻⁴  . 0.18)

[H₃O⁺] = 7.82×10⁻³

- log [H₃O⁺] = pH → - log 7.82×10⁻³

pH = 2.10

5 0
3 years ago
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