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3 years ago

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A block is on a frictionless table, on earth. The block accelerates at 7.5 m/s when a 70 N horizontal force is applied to it. Th

e block and table are set up on the moon. The acceleration due to gravity at the surface of the moon is 1.62 m/s. The weight of the block on the moon is closest to: O 9.5 N O 13 N O 11 N O 15 N O 7.7 N

1 answer:

Liono4ka [1.6K]3 years ago

3 0

Answer:

The weight of the block on the moon is 15 kg.

Explanation:

It is given that,

The acceleration of the block, a = 7.5 m/s²

Force applied to the box, F = 70 N

The mass of the block will be, $m=\dfrac{F}{a}$

$m=\dfrac{70\ N}{7.5\ m/s^2}$

m = 9.34 kg

The block and table are set up on the moon. The acceleration due to gravity at the surface of the moon is 1.62 m/s². The mass of the object remains the same. It weight W is given by :

$W=m\times g$

$W=9.34\ kg\times 1.62\ m/s^2$

W = 15.13 N

or

W = 15 N

So, the weight of the block on the moon is 15 kg. Hence, this is the required solution.

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